Why malleability is a useful property

A 0.060-kg ice hockey puck comes toward a player with a high speed. The player hits it directly back softly with an average forc

kramer

Answer:u=-22 m/s

Explanation:

Given

mass of puck $m=0.06\ kg$

Average force $f_{avg}=1.5\times 10^3\ N$

time of contact $t=1.2ms=1.2\times 10^{-3}\ s$

puck leaves with a velocity of $v=8\ m/s$

We know impulse is $F_{avg}\Delta t$ $=\text{change in momentum}$

therefore

$1.5\times 10^3\times (1.2\times 10^{-3})=P_f-P_i$

$P_i=0.06\times 8-1.8$

$P_i=0.48-1.8=-1.32\ kg-m/s$

Final momentum $P_f=m\times v_f$

$P_f=0.06\times 8$

$P_f=0.48\ kg-m/s$

Impulse on the ball $=F_{avg}\Delta t$

Impulse $=1.5\times 10^3\times 1.2\times 10^{-3}=1.8\ N-s$

Initial velocity is given by

$u=\frac{P_i}{m}=\frac{-1.32}{0.06}$

$u=-22\ m/s$

i.e. initially ball is moving towards -x-axis

8 0

3 years ago

The fine horizontal scratches etched onto a bullet after it has been fired are called?

GalinKa [24]

The fine horizontal scratches etched onto a bullet after it has been fired are called Striations.

<h3>What is Striations?</h3>

Striations are the minute differences in the curve of the bullet's surface. The bullet and the gun barrel are the harder and softer materials, respectively, in firearms evidence.
The striations left on the fired bullet are used as a comparison by firearm examiners.
When a gun is discharged, the bullet blasts down the barrel where it strikes ridges and grooves, spinning and improving shot accuracy.
These ridges cause striations in the bullet's soft metal by digging into it.
An examiner analyses these distinctive markings to verify whether a given bullet was shot from a specific firearm.
A barrel will produce individual markings in addition to a bullet's land and groove impressions as the projectile passes through.

Learn more about Bullet here:

brainly.com/question/6669700

#SPJ4

4 0

2 years ago

PLEASE HELP THIS TEST IS DUE IN TEN MINS

nekit [7.7K]

Answer:

A. A statement of how the volume of a gas is related to its temperature.

3 0

3 years ago

Read 2 more answers

A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma

grigory [225]

Answer:

$\omega=4.2704*10^-^5 rad/s$

Explanation:

Angular Momentum Formula For atoms= $L_{atom}=0.12Nm_{s}h$

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms= $\frac{N_{A}*m}{M}$

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be= $L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h$

Angular Momentum of Sphere= $L_{sphere}=I\omega$

where:

$I=\frac{2mR^{2}}{5}$

So,Angular Momentum of Sphere= $L_{sphere}=\frac{2mR^{2}}{5}\omega$

Angular Momentum of sphere=Angular Momentum of atoms

$L_{sphere}$ = $L_{atom}$

$\frac{2mR^{2}}{5}\omega$ = $0.12\frac{N_{A}m}{M} m_{s}h$

For iron, $m_s =\frac{1}{2}$ . So above equation will become:

$\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }$

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

$\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}$

$\omega=4.2704*10^-^5 rad/s$

5 0

3 years ago

The transfer of heat by the movement of a fluid is called: Think about it: Imagine a pocket of air over the land (“land air”), a

timama [110]

Answer:

The transfer of heat by the movement of fluid is called Convection Heat Transfer

Explanation:

Heat transfer by convection is the transfer of heat by fluid transport from one place to another, such that convection takes place when the heat that comes in contact of fluid containing body is moved to other parts of the container by the transporting fluid

Heat is transferred within a fluid medium mainly by convection (movement of heat by the transfer of fluid particles in the medium)

Convection heat transfer is a combination of conduction and advection heat transfer

7 0

3 years ago