Answer:
Q.1 360° Q.2 360°
Step-by-step explanation:
Q.1 let the third angle of the triangle be a
70°+40°+a=180(by angle sum property)
110°+a=180
a=180°-110°
a=70°
angle x=70°+x=180°(linear angle)
x=180°-70°
x=110°
angle z= 40°+z=180
z= 180°-40°
z=140°
angle y=a+y=180°
70°+y=+80°
y=180°-70°
y=110°
y+z+x=110° +110° +140°=360
Q.2 let the fourth angle of the quadrilateral be x
120°+70°+60°+ x=360° (by angle sum property)
250°+x=360°
x=360°-250°
x=110°
angle a=120°+a=180°(by linear angle)
a=180°-120°
a=60°
angle b=70°+b=180°
b=180°-70°
b=110°
angle c=x+c=180°
110° + c=180°
c=180°-110°
c=70°
angle d=60°+d=180°
d= 180° -60°
d=120°
a+b+ c+d=120°+110°+60°+70°=360°
