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RideAnS [48]
3 years ago
10

when drawing a scatter diagram, along which axis is the explanatory variable placed? along which axis is the response variable p

laced?
Physics
1 answer:
eimsori [14]3 years ago
6 0
The explanatory variable is placed on the x-axis and the response variable is placed on the y-axis.
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3 years ago
What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is
QveST [7]
Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "

Solution
The force exerted on a charge q by an electric field E is given by
</span>F=qE
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>E=k_e  \frac{Q}{r^2}
with k_e = 8.99\cdot 10^9 Nm^2/C^2, Q=+25 nC=25 \cdot 10^{-9}C is the charge on the bead. We want to calculate the field at r=4.0 cm=0.04 m:
E=(8.99\cdot 10^9) \frac{25\cdot 10^{-9}}{(0.04)^2}=1.4\cdot 10^5 V/m
The proton has a charge of q=1.6\cdot 10^{-19}C, therefore the force exerted on it is
F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N

And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass, m=1.67\cdot 10^{-27} kg, we have
F=ma
a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2

The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
a=-1.35 \cdot 10^{13} m/s^2
6 0
3 years ago
What is the magnetic force on a proton that is moving at 4.5 x 10^7 m/s to the right through a magnetic field that is 1.6 T and
Agata [3.3K]
The magnetic force on a charged particle is given as: F = qvBsinФ
B is the magnetic field.
q is the charge on the particle.
v is the velocity of the charged particle.
 Ф is the angle between magnetic field (B) & the velocity of charge (v).


⇒ F = qvb sin Ф

Here, Ф = 90 degree.
and sin 90 = 1
Putting the values in the equation, we get,

F = 1.6 x 10^-19 C × 4.5 × 10^7 m/s × 1.6 T
= 11.52 × 10^-12N
= 1.2 x 10^-11 N up
4 0
3 years ago
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