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2 years ago

a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin

Physics

1 answer:

Daniel [21]2 years ago

7 0

This question involves the concepts of Wein's displacement law and characteristic wavelength.

The blackbody temperature will be "3.22 x 10⁵ k".

<h3>WEIN'S DISPLACEMENT LAW</h3>

According to Wein's displacement law,

$\lambda_{max} T = c\\\\T=\frac{c}{\lambda_{max}}$

where,

$\lambda_{max}$ = characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
T = temperature = ?
c = Wein's displacment constant = 2.897 x 10⁻³ m.k

Therefore,

$T=\frac{2.897\ x\ 10^{-3}\ m.k}{9\ x\ 10^{-9}\ m}$

T = 3.22 x 10⁵ k

Learn more about characteristic wavelength here:

brainly.com/question/14650107

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3 years ago

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$A_3=2.2 cm^2=2.2\times 10^{-4} m^2$

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$R=\frac{\rho l}{A_1}+\frac{\rho l}{A_2}+\frac{\rho l}{A_3}+\frac{\rho l}{A_4}$

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Substitute the values

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3 years ago

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