a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin
1 answer:
This question involves the concepts of Wein's displacement law and characteristic wavelength.
The blackbody temperature will be "3.22 x 10⁵ k".
<h3>WEIN'S DISPLACEMENT LAW</h3>According to Wein's displacement law,
where,
= characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
- T = temperature = ?
- c = Wein's displacment constant = 2.897 x 10⁻³ m.k
Therefore,
T = 3.22 x 10⁵ k
Learn more about characteristic wavelength here:
You might be interested in
<h2>Answer:</h2>
<em>Hello, </em>
<h3><u>QUESTION)</u></h3>According to the second Newton's Law,
<em>✔ We have : F = m x a ⇔ m = F/a </em>
- m = 3000/15
- m = 200 kg
The mass of the object is therefore 200 kg.
Answer:
Explanation:
Given that,
The mass of a Hubble Space Telescope,
It orbits the Earth at an altitude of
We need to find the potential energy the telescope at this location. The formula for potential energy is given by :
Where
is the mass of Earth
Put all the values,
So, the potential energy of the telescope is .