a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin
1 answer:
This question involves the concepts of Wein's displacement law and characteristic wavelength.
The blackbody temperature will be "3.22 x 10⁵ k".
<h3>WEIN'S DISPLACEMENT LAW</h3>According to Wein's displacement law,
where,
= characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
- T = temperature = ?
- c = Wein's displacment constant = 2.897 x 10⁻³ m.k
Therefore,
T = 3.22 x 10⁵ k
Learn more about characteristic wavelength here:
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Each internal angle is 540/5 = 108°.
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To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:
For a gas transformation, this law can be rewritten as
(1)
where 1 and 2 label the initial and final conditions of the gas.
Before applying the law, we must convert the temperatures in Kelvin:
The initial volume of the gas is
, so if we re-arrange (1) we find the new volume of the gas:
For a gas transformation, this law can be rewritten as
where 1 and 2 label the initial and final conditions of the gas.
Before applying the law, we must convert the temperatures in Kelvin:
The initial volume of the gas is