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Rus_ich [418]
3 years ago
12

a blackbody is radiating with a characteristic wavelength of 9 microns what is the blackbody temperature answer in kelvin

Physics
1 answer:
Daniel [21]3 years ago
7 0

This question involves the concepts of Wein's displacement law and characteristic wavelength.

The blackbody temperature will be "3.22 x 10⁵ k".

<h3>WEIN'S DISPLACEMENT LAW</h3>

According to Wein's displacement law,

\lambda_{max} T = c\\\\T=\frac{c}{\lambda_{max}}

where,

  • \lambda_{max} = characteristic wavelength = 9 μm = 9 x 10⁻⁹ m
  • T = temperature = ?
  • c = Wein's displacment constant = 2.897 x 10⁻³ m.k

Therefore,

T=\frac{2.897\ x\ 10^{-3}\ m.k}{9\ x\ 10^{-9}\ m}

T = 3.22 x 10⁵ k

Learn more about characteristic wavelength here:

brainly.com/question/14650107

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6. A golf ball is hit a distance of 300 yards in 10 sec. What is the speed of the golf ballo
katen-ka-za [31]

The speed of the ball is 27.4 m/s

Explanation:

The speed of an object is given by:

speed=\frac{d}{t}

where

d is the distance covered

t is the time taken

In this problem, we have:

d = 300 yards is the distance covered by the golf ball

t = 10 s is the time taken

Keeping in mind that

1 yard = 0.914 m

We can convert the distance from yards to meters:

d = 300 \cdot 0.914 = 274.2 m

And substituting into the equation, we find the speed of the ball:

speed=\frac{274.2}{10}=27.4 m/s

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0
3 years ago
A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?
Vesna [10]
6.3 That Would be the I answer I think but Check on Google For the formula
6 0
3 years ago
Which scientist proved experimentally that a shadow of the circular object illuminated 18. with coherent light would have a cent
Zina [86]

Answer:

Your answer is( D) - Arago

8 0
3 years ago
A 900 kg vehicle moves around a curve with an incline of 20\circ∘ at a speed of 12.5 m/s. If the curve has a radius of 50 meters
valentina_108 [34]

Answer:

The normal force experienced by the car is approximately 8223.2 N

Explanation:

The question relates to banking of road where the centripetal force for the circular motion of the vehicle is provided by the horizontal component of the normal reaction

The mass of the vehicle that moves around the curve, m = 900 kg

The incline of the curve, θ = 20°

The speed with which the vehicle moves around the curve, v = 12.5 m/s

The radius of the curve, R = 50 meters

We have;

N \cdot sin(\theta) = \dfrac{m \cdot v^2}{R}

Where;

θ = The angle of inclination of the road = 20°

N = The normal force experienced by the car

m = The mass of the car = 900 kg

v = The velocity with which the car is moving = 12.5 m/s

R = The radius of the curve around which the vehicle moves = 50 m

\therefore N = \dfrac{m \cdot v^2}{R \cdot sin(\theta)} = \dfrac{900 \times (12.5)^2}{50 \times sin(20^{\circ})}  = 8223.1998754586828969046217875927

The normal force experienced by the car = N ≈ 8223.2 N.

6 0
3 years ago
5. Identify the reactants in this chemical equation:<br> 2H3PO4 → HAP20, +H2O
mixas84 [53]

Answer:

H=Hydrogen, PO4=Phosphate

Explanation:

Reactions are on the left side of arrow and products are on the right side of arrow.

4 0
2 years ago
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