A bag is gently pushed off the top of a wall at A and swings in a vertical plane at the end of a rope of length l. Determine the
angle θ for which the rope will break, knowing that it can withstand a maximum tension equal to twice the weight of the bag.
1 answer:
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Answer:
240 m
120 m
Explanation:
d = Path difference = 120 m
For destructive interference
Path difference
The longest wavelength is 240 m
For constructive interference
The longest wavelength is 120 m
Since initial velocity is zero hence , u = 0
=> d = 1/2 * a * t2
on solving we get
d = 86.436 metres
Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2
Explanation :
It is given that :
The initial velocity of the car is 10 m/s.
Juliette sets the acceleration to zero.
We know that, acceleration \
where,
u is the initial velocity and v is the final velocity.
So, final velocity will become 10 m/s.
Hence, the car will move with the constant velocity i.e. 10 m/s.
So, Shakina described that the car will move with the constant velocity of 10 m/s as acceleration is zero.