The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.
Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.
Let us consider the two positive real numbers as x and y. Then, their sum is written as,
x+y=108
Then, y=108-x
And the product is written as,
P=xy²
Substitute value of y in the above equation, we get,

Now, differentiate P with respect to x, and we get,

Solving the above equation to zero, we get,

Substitute values of x in y=108-x, to get values of y.
If we substitute x=108, we get the y value as zero which doesn't give the required solution.
But, if we substitute x=36, we get,

Thus, the two positive numbers are 36 and 72.
To know more about positive numbers:
brainly.com/question/1635103
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