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Norma-Jean [14]
3 years ago
12

A ball of mass 1.6 kg is attached to the end of a massless string. A circus clown twirls the

Physics
1 answer:
erik [133]3 years ago
7 0

Compute the ball's angular speed <em>v</em> :

<em>v</em> = (1 rev) / (2.3 s) • (2<em>π</em> • 180 cm/rev) • (1/100 m/cm) ≈ 4.917 m/s

Use this to find the magnitude of the radial acceleration <em>a</em> :

<em>a</em> = <em>v </em>²/<em>R</em>

where <em>R</em> is the radius of the circular path. We get

<em>a</em> = <em>v</em> ² / (180 cm) = <em>v</em> ² / (1.8 m) ≈ 13.43 m/s²

The only force acting on the ball in the plane parallel to the circular path is the tension force. By Newton's second law, the net force acting on the ball has magnitude

∑ <em>F</em> = <em>m</em> <em>a</em>

where <em>m</em> is the mass of the ball. So, if <em>t</em> denotes the magnitude of the tension force, then

<em>t</em> = (1.6 kg) (13.43 m/s²) ≈ 21 N

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3 years ago
A cop claims you passed him at more than 60 mph ,27.8 meters per second, 200 meters from a red light that just turned green. you
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Sounds like the situation is modeled like so:

[Light] - - - - - - - - - - [You] => - - -

- - - - - - - - - - - - - - - [Cop] - - - - -

<= = = 200 m = = =>

where your velocity is 27.8 m/s to the right. So the question is asking, is it possible that your car, given that it accelerates at a maximum of 1/5 m/s^2, can reach a speed of 27.8 m/s from rest in the time it takes for it to cover 200 m.

The car's position at time t is

x=\dfrac12\left(1.5\dfrac{\rm m}{\mathrm s^2}\right)t^2

The time it takes to traverse 200 m is

200\,\mathrm m=\left(0.75\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t\approx16.3\,\mathrm s

Your car's velocity at time t, starting from rest, is

v=\left(1.5\dfrac{\rm m}{\mathrm s^2}\right)t

so that after 16.3 s, your car is moving at a speed of

v=\left(1.5\dfrac{\rm m}{\mathrm s^2}\right)\left(16.3\,\mathrm s\right)\approx24.5\dfrac{\rm m}{\rm s}

which is less than the speed the cop claims you were going, so the cop is not correct.

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4 years ago
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3 years ago
A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decele
OlgaM077 [116]

Answer:

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Explanation:

W=f*d

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<u>To find work:</u>

Now that the force and the distance are known, plug and chug:

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Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

<u>198785.714286 Joules</u>

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