B
In quadrant 2, the x values are negative and the y values are positive
Answer:
A relation from a set of inputs to a set of possible outputs where each input is related to exactly one output
Step-by-step explanation:
Answer:
The selling price that will maximize profit is $56.
Step-by-step explanation:
Given : It costs 12 dollars to manufacture and distribute a backpack. If the backpacks sell at x dollars each, the number sold, n, is given by ![n=\frac{2}{x-12}+7(100-x)](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B2%7D%7Bx-12%7D%2B7%28100-x%29)
To find : The selling price that will maximize profit ?
Solution :
The cost price is $12.
The selling price is $x
Profit = SP-CP
Profit = x-12
The profit of n number is given by,
![P=(x-12)n](https://tex.z-dn.net/?f=P%3D%28x-12%29n)
Substitute the value of n,
![P=(x-12)(\frac{2}{x-12}+7(100-x))](https://tex.z-dn.net/?f=P%3D%28x-12%29%28%5Cfrac%7B2%7D%7Bx-12%7D%2B7%28100-x%29%29)
![P=\frac{2(x-12)}{x-12}+7(100-x)(x-12)](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B2%28x-12%29%7D%7Bx-12%7D%2B7%28100-x%29%28x-12%29)
![P=2+7(100x-1200-x^2+12x)](https://tex.z-dn.net/?f=P%3D2%2B7%28100x-1200-x%5E2%2B12x%29)
![P=2+700x-8400-7x^2+84x](https://tex.z-dn.net/?f=P%3D2%2B700x-8400-7x%5E2%2B84x)
![P=-7x^2+784x-8398](https://tex.z-dn.net/?f=P%3D-7x%5E2%2B784x-8398)
Derivate w.r.t x,
![\frac{dP}{dx}=-14x+784](https://tex.z-dn.net/?f=%5Cfrac%7BdP%7D%7Bdx%7D%3D-14x%2B784)
Put it to zero for critical point,
![-14x+784=0](https://tex.z-dn.net/?f=-14x%2B784%3D0)
![-14x=-784](https://tex.z-dn.net/?f=-14x%3D-784)
![x=\frac{-784}{-14}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-784%7D%7B-14%7D)
![x=56](https://tex.z-dn.net/?f=x%3D56)
Derivate again w.r.t x, to determine maxima and minima,
![\frac{d^2P}{dx^2}=-14](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5E2P%7D%7Bdx%5E2%7D%3D-14%3C0)
It is a maximum point.
Therefore, the selling price that will maximize profit is $56.
Answer:
Step-by-step explanation:
i am on the same one
6 people per group 6 people * 4 groups = 24 portions