Estimate the weight of a 1000kg car that is accelerating at 3 m/s/s.
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Answer:
<h2>Magnitude of the second charge isExplanation:
According to columbs law;
F =
F is the attractive or repulsive force between the charges = 12N
q1 and q2 are the charges
let q1 = - 8.0 x 10^-6 C
q2=?
r is the distance between the charges = 0.050m
k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²
On substituting the given values
12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²
Cross multiplying
Answer:
12m/s
Explanation:
Given parameters:
Power = 6.5 x 10⁴W
Force = 5.5 x 10³N
Unknown:
The resulting velocity = ?
Solution:
The velocity of a body is related to force and power using the expression below;
Power = Force x velocity
Insert the parameters and solve for velocity
6.5 x 10⁴ = 5.5 x 10³ x velocity
velocity = = 12m/s