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frutty [35]
3 years ago
7

Estimate the weight of a 1000kg car that is accelerating at 3 m/s/s.

Physics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

W = 9800  N

Explanation:

Given that,

Mass of a car, m = 1000 kg

Acceleration of the car, a = 3 m/s²

We need to find the weight of the car. Weight of an object is given by the product of mass and acceleration due to gravity on the Earth.

W = mg

Put all the values,

W = 1000 kg × 9.8 m/s²

= 9800  N

So, the weight of the car is 9800  N.

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What is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
Art [367]

CORRECT ANSWER:

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

STEP-BY-STEP EXPLANATION:

The complete question from book is

According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.

c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.

d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.

e- None of the other answer options is correct.

3 0
3 years ago
What is the frequency of sound waves whose wavelength is 0.25 m on a day when the air temperature is 25 degree Celsius? Group of
Dvinal [7]

Answer:1384 Hz

Explanation:

Given

wavelength(\lambda )=0.25 m

Temperature T=25^{\circ}

at T=25^{\circ} velocity of sound is 346 m/s

and we know

velocity=frequency\times \lambda

v=f\times \lambda

346=f\times 0.25

f=1384 Hz

5 0
3 years ago
Read 2 more answers
While traveling along a highway a driver slows from 32 m/s and comes to a stop with an acceleration of -6 m/s2. How long did it
diamong [38]

Answer: 6s

Explanation:

Vs=32m/s  speed at beginning of slowing down

Vf=0m/s     stop speed

a= -6 m/s²  acceleration

----------------

Use equation for acceleration :

a=(Vf-Vs)/t

a*t=Vf-Vs

t=(Vf-Vs)/a

t=(0-36)/-6

t=-36/-6

t=6 s

7 0
3 years ago
A cannon fires a 0.652 kg shell with initial
laila [671]
 Mass have no effect for the projectile motion and  u want to know the  height "h"   
first,
        find the vertical and horizontal components of velocity 
 vertical component of velocity = 12 sin 61                  
horizontal component of velocity = 12 cos 61
now for the vertical motion ;               
             S = ut + (1/2) at^2
where
 s = h 
u = initial vertical component of velocity 
t = 0.473 s 
a = gravitational deceleration (-g) = -9.8 m/s^2    
       
         h=[12×sin 610×0.473]+[−9.8×(0.473)2] 

u can simplify this and u will get the answer

h=.5Gt2 

H=1.09m
6 0
3 years ago
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What types of materials can make up sediments?
GREYUIT [131]

Answer: Pieces of minerals, rocks, plant and animal remains.

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4 0
3 years ago
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