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frutty [35]
3 years ago
7

Estimate the weight of a 1000kg car that is accelerating at 3 m/s/s.

Physics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

W = 9800  N

Explanation:

Given that,

Mass of a car, m = 1000 kg

Acceleration of the car, a = 3 m/s²

We need to find the weight of the car. Weight of an object is given by the product of mass and acceleration due to gravity on the Earth.

W = mg

Put all the values,

W = 1000 kg × 9.8 m/s²

= 9800  N

So, the weight of the car is 9800  N.

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A car is moving at a velocity of 25 ms-1.
lianna [129]
Velocity = 25 + (6x3)= 43 m/s
3 0
3 years ago
A Foucault pendulum consists of a brass sphere with a diameter of 32.0 cm suspended from a steel cable 10.0 m long (both measure
Sergio039 [100]

Answer:

T = 44.35 °C

Explanation:

d = 32cm

R = 16 cm

Lsteel = 10m

T1 = 20° C

Space = 0.3cm

The space between the sphere and the floor is represented by δL(total) after the temperature increases.

As the temperature increases, both will expand.

So,

0.3 x 10^(-2) = δL(steel) + δR(brass)

= {L(o) x α(steel) x δT} + {R(o) x {α(brass) x δT}

= {10 x 1.2 x 10^(-5) x (T-20)} + {0.16 x 2 x 10^(-5) x (T-20)}

= 12.32 x 10^(-5) x(T-20)

Therefore (T-20) = (0.3 x 10^(-2)) / {12.32 x 10^(-5)}

T = 20 + 24. 35 = 44.35 °C

8 0
3 years ago
An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equi
tino4ka555 [31]

Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

<h3>What is Simple Harmonic Motion?</h3>
  • A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force.
  • The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.
  • If x is the displacement from the mean position, and F is the restoring force, then

                   F∝-x

                   F=-kx where, k is called the spring constant.

<h3>How to approach the problem?</h3>
  • Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.
  • Here, from the question given, we can write, x=-0.400m and F=230N.
  • Thus, our spring constant k will be,

                       k=-F/x= (230)/ (0.400) =575 N/m.

Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.

Learn more about the Simple Harmonic Motion here:

brainly.com/question/28019840

#SPJ4

<h3 />

8 0
2 years ago
Simple machines ________ the amount of work needed to lift an object.
weqwewe [10]
B: Reduce!!......................
6 0
3 years ago
If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point
Oxana [17]

Answer:

Because of the interstellar dust and interior location of the solar system.

Explanation:

We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

<u>So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.</u>

5 0
3 years ago
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