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Alex777 [14]
3 years ago
14

what is the kinetic energy of a hammer that starts from rest and decreases its potential energy by 10k?

Physics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

20..................

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The distance a toy car travels over time is shown in the graph.
maria [59]

Answer:

Explanation:what’s the answer ?

3 0
3 years ago
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If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number
Misha Larkins [42]

Answer:

the question is incomplete, here is the complete question.

"On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?

1.09 atm

Explanation:

the question addresses an ideal gas. where the relationship between the volume(v),pressure(p),temperature(T) and nos of molecules(n) is expressed as

PV=nRT\\

Where R us the ideal gas constant.

From the question,the number of molecules,volume are constant, we can now re-write the equation as

       P=KT\\

where pressure and temperature are the only varying parameters.

if we vary the constant K we arrive at

\frac{P_{1} }{T_{1}}=\frac{P_{1} }{T_{1}}=...=\frac{P_{n} }{T_{N}}\\

since  the Temprature must be in absolute temperature, we add 273k to it Celsius value.

T_{1} =12+273=285k\\T_{2} =37+273=310k\\P_{1} =1 atm\\

Substituting value into the generated equation, we have

P_{2}=\frac{310*1}{285} \\P_{2}=1.09 atm.\\

7 0
3 years ago
Can someone help me with any of these problems or all of them? It will get you an easy ten points per question
MrRa [10]

Answer: For number 9, the children would not be able to close the box.

Explanation: The combined force of the children is 55 N. The box spring overpowers them with 60 N. I hope this helps!

6 0
4 years ago
A small metal sphere has a mass of 0.14 g and a charge of -22.0 nc . it is 10 cm directly above an identical sphere with the sam
jonny [76]
For this problem, we use the Coulomb's law written in equation as:

F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹ 
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects

Substituting the values:

F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
6 0
4 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s,
IRINA_888 [86]

Explanation:

If the distance between the bottom of the ladder and the wall is x, then:

cos θ = x / 10

Taking derivative with respect to time:

-sin θ dθ/dt = 1/10 dx/dt

Substituting for θ:

-sin (acos(x / 10)) dθ/dt = 1/10 dx/dt

Given that x = 6 and dx/dt = 1.1:

-sin (acos(6/10)) dθ/dt = 1/10 (1.1)

-0.8 dθ/dt = 0.11

dθ/dt = -0.1375

The angle is decreasing at 0.1375 rad/s.

3 0
3 years ago
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