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Musya8 [376]
3 years ago
12

What is the mass of a 4900 N bobsled

Physics
2 answers:
damaskus [11]3 years ago
7 0

Answer:

500 Kg.

Explanation:

The problem is giving us the weight of the object the weight is different from the mass of an object

Weight is the mass of any object multiplied by gravity (<em>the value of gravity is approximately  9.8\frac{m}{s^2} ).</em>

The unit of weight are newtons that equals

N= Kg.\frac{m}{s^2}

W= m.g

we cleared the mass of the formula

W=m.g\\ m=\frac{W}{g} \\ m= \frac{4900N}{9.8 \frac{m}{s^2} }= 500 Kg

tensa zangetsu [6.8K]3 years ago
6 0
A single kilogram is equivalent to 9.8 newtons, meaning that to find the weight of the bobsled, you would simply divide the weight by 9.8. Doing this we find that the bobsled is 500kg

4900 / 9.8 = 500
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The number of mushrooms needed by a pizza restaurant is given by the
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Explanation:

Given the following equation:

g=3n

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g=3(8)

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8 0
3 years ago
A beam of electrons is sent horizontally down the axis of a tube to strike a fluorescent screen at the end of the tube. On the w
slamgirl [31]

Answer:

The answer is 3.

Explanation:

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So as a result of the magnetic field directed vertically downwards which is at a right angle with the electron beams, the electrons will move to the right and the spot will be deflected to the right of the screen when looking from the electron source.

I hope this answer helps.

4 0
3 years ago
A boy is pulling a load of 150N with a string inclined at an angle 30 to the horizontal if the tension of string is 105N the for
Lorico [155]

The force tending to lift the load (vertical force) is equal to <u>22.5N.</u>

Why?

Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.

We can calculate the vertical force using the following formula:

VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N

Hence, we can see that <u>the force tending to lift the load</u> off the ground (vertical force) is equal to <u>22.5N.</u>

Have a nice day!

8 0
3 years ago
A woman pushes an oak chest across an oak floor at a constant speed of 0.450 m/s. The chest has a mass of 40.0 kg, and the coeff
natima [27]

Answer:

A. 243 N

Explanation:

Friction is the force that opposes the relative motion between systems that are in contact.

This friction force that opposes the motion of the oak chest across the oak surface will be equal and opposite to that exerted by the woman.

First find the normal force which is the force that would point directly upwards to support weight of the block.

Normal force, N= mg where m is the mass of the chest and g is the acceleration due to gravity.

Given m=40 kg and g=9.80 m/s²

N force=40×9.80 =392N

Then find the force of friction which is given by the formula;

<em>F=μN where μ is friction coefficient for the  oak chest  and N is the normal force on the chest</em>

Given <em>μ</em>=0.620  and N force = 392 N then it will be;

F=0.620× 392 =243.04 N

Answer : 243 N

6 0
3 years ago
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