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saul85 [17]
3 years ago
13

Am sorry for dripping but dripping is what i do

Mathematics
2 answers:
Anestetic [448]3 years ago
6 0

And one of these days, I'm gon' get dressed

And drip all over you

Bogdan [553]3 years ago
4 0

Step-by-step explanation:

and one of these day I must get straigh and drip all over you

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Help timed quizzes giving !!
fenix001 [56]

9.57

2.57 + 1.7= 4.27

4.27 + 5.3 = 2.57

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3 years ago
A + 3 + 2a = -1 + 3a + 4
Verdich [7]

Answer:The answer is Equal.

Step-by-step explanation:First you need to add A and 2A together. that equals 3a. Since 3 is left , it could be -1 and 4 because it would equal the same thing hope this helped :)

8 0
3 years ago
What is the value of X
erica [24]

Answer:

x=3

Step-by-step explanation:

the sides MJ and MK should be equal so 12x-24 = 4x

if you isolate x you get 3

3 0
3 years ago
Read 2 more answers
Triangle FGH is similar to triangle IJK. Find the measure of side KI. Round your
erastovalidia [21]

Answer:

5.8

Step-by-step explanation:

Similar shapes also maintain a constant proportion of sides. Therefore, we can set up the following equation:

\frac{31}{43}=\frac{\text{KI}}{8}

Solving, we get:

\text{KI}=\frac{8\cdot 31}{43}\approx \boxed{5.8}

5 0
3 years ago
4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t
Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

a_{n}=a_{1}r^{n-1}

a_{1} = the first term of the series

r = the geometric ratio

a_{1} would represent the height at which the ball is first dropped. Therefore:

a_{1} = k

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

r=\frac{3}{4}

Our general term would be:

a_{n}=a_{1}r^{n-1}

a_{n}=k(\frac{3}{4}) ^{n-1}

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

k represents the initial height:

k = 235\ ft

n represents the number of times the ball bounces:

n = 6

Plugging this back into our general term of the geometric series:

a_{n}=k(\frac{3}{4}) ^{n-1}

a_{n}=235(\frac{3}{4}) ^{6-1}

a_{n}=235(\frac{3}{4}) ^{5}

a_{n}=55.8\ ft

a_{n} represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. ​

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

We already know these variables:

a_{1}= k = 235\ ft

r=\frac{3}{4}

n = 12

Therefore:

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

S_{n}=(4)(235)(1-\frac{3}{4} ^{12})

S_{n}=910.22\ ft

8 0
3 years ago
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