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2 years ago

Copper chloride burns bright green 510x10^9 m what is the frequency in Hz?

Chemistry

1 answer:

Katen [24]2 years ago

5 0

Answer:

5.88 x 10⁻⁴Hz

Explanation:

Given parameters:

Wavelength = 510 x 10⁹m

Unknown:

Frequency = ?

Solution:

To solve this expression, we use the equation below:

V = f∧

V is the velocity = 3 x 10⁸m/s

f is the frequency

∧ is the wavelength

3 x 10⁸ = f x 510 x 10⁹

f = 5.88 x 10⁻⁴Hz

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Question 7.

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$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}$

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

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(b) Calculation

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Volume=V=3L
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Temp=T=25°C

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$\\ \rm\rightarrowtail PV=nRT$

$\\ \rm\rightarrowtail n=\dfrac{PV}{RT}$

$\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}$

$\\ \rm\rightarrowtail n=2442/25R$

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