Question

If two people who are both heterozygous for the trait of a bent pinky finger have a child, what are the possible genotypes and phenotypes?

Answer 1

genotypes is 1:2:1 & phenotypes is 3:1

l hope this helps you

Answer 2

Answer:

When two people heterozygous for the trait of a bent pinky finger have a child, the possible genotypes CC, Cc and cc -in a ratio of 1:2:1- being the phenotypes bent pinkies: straight pinkies in a ratio of 3:1.

Explanation:

Bent pinky finger is due to a condition called Camptodactyly, characterized by sustained bending of a finger due to a deformity in an interphalangeal joint. Pinky finger camptodactyly is a trait that is inherited in an autosomal dominant pattern.

• With camptodactyly (bent pinky finger) C
• Without camptodacilia (straight pinky finger) c

The parental generation is made up of two heterozygous individuals with bent pinky fingers:

♂ Cc

♀ Cc

The offspring of this hybrid cross, according to Mendelian heritage, can be seen in this Punnett Square:

Alleles       C     c

C             CC   Cc

c             Cc    cc

According to this the offspring will have:

Genotypes:

CC: 25%

Cc: 50%.

cc: 25%

Phenotypes:

Bent pinky finger: 75%

Straight pinky finger: 25%