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3 years ago

PLEASE HELP A GIRL OUT!!! What is the best estimate for the value of the expression?

Mathematics

1 answer:

Ivenika [448]3 years ago

5 0

Answer: -2(1/2)

Step-by-step explanation:

I CAN HELP A GIRL OUT!

anyways...

calculate the difference first.

(-13/12) - 14/9

then, rewrite the expression.

-13/12 - 14/9

the solution is -95/36.

when it's converted to decimal form, it turns into -2.638. so, our BEST estimate for the value of the expression is -2(1/2) (the second option)

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Pls help my with one and two asap

Dafna11 [192]

Answer:

Step-by-step explanation:

for nr. 1

sum of angles in a triangle=180

x=180-(81+84)=15

acute triangle

for nr.2

x=180-(24+36)=120

obtuse triangle

4 0

3 years ago

Find an area of a triangle with a base of 25 feet and height of 8 feet. What’s the formula for a triangle?

marissa [1.9K]

Answer:

100 feet squared: can u plz give me the brainliest answer!!!!!!!!! plz!!!!!!!!!!!

Step-by-step explanation:

Area of triangle: base x height divided by 2.

25 x 8 = 200

200/2 = 100

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3 years ago

(a+b)²=?ahihihihihihihihihihihihi

aleksandr82 [10.1K]

Answer:

(a+b)²=a²+2ab+b²

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

Find the missing angle according to the Triangle Exterior Angle Theorem

Alexxandr [17]

Answer:

k = 36

Step-by-step explanation:

By exterior angle theorem:

$k \degree + 110 \degree = 146 \degree \\ \\ k \degree = 146 \degree - 110 \degree \\ \\ k \degree = 36\degree \\ \\ k = 36$

6 0

3 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago