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Goryan [66]
3 years ago
6

Assuming that Coca-Cola has the same specific heat as water [4.18 J/(g°C)]. Calculate the amount of heat in kilojoules transferr

ed when one can (about 350 gg) is cooled from 21°C to 8°C.
Chemistry
1 answer:
enyata [817]3 years ago
7 0

Answer:

Heat transferred in the process is 19019J

Explanation:

Using the equation:

Q = S×m×ΔT

We can solve the energy transferred in the process, Q, where:

S is specific heat = 4.18J /(g°C)

m is mass = 350g

ΔT is change in temperature (21°C - 8°C = 13°C)

Q = 4.18J/(g°C)×350g×13°C

Q = 19019J

<h3>Heat transferred in the process is 19019J</h3>

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You want to determine the value of x in hydrated iron II sulfate, FeSO4 xH2O. In the laboratory you weigh out 1.983 g of the hyd
jek_recluse [69]

Answer:

The value of x is 7.

Explanation:

When a hydrated salt is heated, the water evaporates because it has a lower boiling point (373 K) and what remains is the <em>anhydrous salt</em> (without water) The mass of the hydrated salt is equal to the sum of the anhydrous salt and the water. Since we have 2 of these 3 data, we can look for the mass of water.

mass of FeSO₄.xH₂O = mass of FeSO₄ + mass of H₂O

mass of H₂O = mass of FeSO₄.xH₂O - mass of FeSO₄

mass of H₂O = 1.983g - 1.084g = 0.899g

This means that 0.899g of water accompany 1.084 g of the salt. We want to know how many grams of water accompany 1 mol of the salt (in the molecular formula we have 1 mol of FeSO₄). Since the molar mass of  is 152g/mol, we can establish:

1mol(FeSO_{4} ).\frac{152gFeSO_{4}}{1mol(FeSO_{4} )} .\frac{0.899gH_{2}O }{1.084gFeSO_{4}} =126gH_{2}O

As a result 1 mol of FeSO₄ is accompanied by 126 g of water. If we pass that mass into moles:

126gH_{2}O.\frac{1molH_{2}O}{18gH_{2}O}  =7molH_{2}O

Finally, the number of moles of water in the molecular formula is x = 7.

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Why graphite does have a metallic cluster
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Due to Presence of free electrons.

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