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Gekata [30.6K]
3 years ago
11

What is the oxidation number of nitrogen in the nitrate ion NO3^1-​

Chemistry
1 answer:
harina [27]3 years ago
5 0

Answer:

+5

Explanation:

You use the rules for oxidation numbers to calculate that the oxidation number of N is +5.

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According to the VSEPR theory, a molecule or ion of NH₃ will have a _____ shape.
Elan Coil [88]

Answer:

B) flat trigonal

Explanation:

All the Hydrogen atoms are arranged symmetrically around the Nitrogen atom which forms the base, and the two nonbonding electrons form the tip

4 0
3 years ago
Read 2 more answers
What volume of nitrogen gas at STP would react with 37.2 g of magnesium to produce magnesium nitride
anastassius [24]

Answer:

11.58 L of N₂

Explanation:

We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:

Mass of Mg = 37.2 g

Molar mass of Mg = 24 g/mol

Mole of Mg =?

Mole = mass /Molar mass

Mole of Mg = 37.2 / 24

Mole of Mg = 1.55 moles

Next, we shall write the balanced equation for the reaction. This is illustrated below:

3Mg + N₂ —> Mg₃N₂

From the balanced equation above,

3 moles of Mg reacted with 1 mole of N₂.

Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂

Thus, 0.517 mole of N₂ is need for the reaction.

Finally, we shall determine the volume of N₂ needed for the reaction as follow:

Recall:

1 mole of a gas occupies 22.4 L at STP.

1 mole of N₂ occupied 22.4 L at STP.

Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP

Thus, 11.58 L of N₂ is needed for the reaction.

6 0
3 years ago
In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo
NNADVOKAT [17]

Answer:

- 178 ºC

Explanation:

The  ideal gas law   states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁    (1)

and for the final conditions:

P₂V₂= n₂ R T₂    where   n₂ = n₁/2     then    P₂ V₂ = n₁/2 T₂    (2)

Assuming V₂ = V₁ and  dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂  / ( n₁ R T₁)      then  P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

T₂ = 95 - 273 = - 178 º C

6 0
3 years ago
Critical practices to control the amount of solid waste include __________.
erica [24]
Reduce, reuse, recycle, compost. I think hope its helpful.
3 0
3 years ago
Read 2 more answers
Did Chelate compounds increase the rate of reaction?
Viefleur [7K]

Answer:

Chelate, any of a class of coordination or complex compounds consisting of a central metal atom attached to a large molecule, called a ligand, in a cyclic or ring structure. An example of a chelate ring occurs in the ethylenediamine-cadmium complex:

The ethylenediamine ligand has two points of attachment to the cadmium ion, thus forming a ring; it is known as a didentate ligand. (Three ethylenediamine ligands can attach to the Cd2+ ion, each one forming a ring as depicted above.) Ligands that can attach to the same metal ion at two or more points are known as polydentate ligands. All polydentate ligands are chelating agents.

Chelates are more stable than nonchelated compounds of comparable composition, and the more extensive the chelation—that is, the larger the number of ring closures to a metal atom—the more stable the compound. This phenomenon is called the chelate effect; it is generally attributed to an increase in the thermodynamic quantity called entropy that accompanies chelation. The stability of a chelate is also related to the number of atoms in the chelate ring. In general, chelates containing five- or six-membered rings are more stable than chelates with four-, seven-, or eight-membered rings.

Explanation:

7 0
2 years ago
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