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Blababa [14]
3 years ago
13

I need filling the blank spots ​

Chemistry
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

have you tried c

Explanation:

the chicken and I don't know if you can make it

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Method that used to separate kerosine and water?
nata0808 [166]
You can use a separating funnel. The person will go the top and the water to the bottom.
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3 years ago
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6547.9 feet to meters<br> Using dimensional analysis
ELEN [110]

Answer:

92.964

Explanation:

8 0
3 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
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This figure (Figure 1)shows a container that is sealed at the top
guajiro [1.7K]
I'm pretty sure the answer is 0.833 atm.

Hope I helped! <3

-cara
7 0
3 years ago
How many water molecules are created when 32 grams of oxygen react completely with 4.0 grams of hydrogen?
ch4aika [34]

Answer:

d. 1.2 × 1024

Explanation:

From the equation of reaction

2H2 + O2= 2H2O

i.e 2mole(4g) of hydrogen requires 1 mole(32g) of oxygen to produce 2mole (2×6.02×10^23 molecules) of H2O= 1.2×20^24 molcules of water.

NB: 1 mole of H2O contains 6.02×10^23 molecules of H2O

3 0
3 years ago
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