How many moles of Al2O3 can be formed from 10.0 g of Al?
1 answer:
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27.9L
Explanation:
Given parameters:
Number of molecules = 7.5 x 10²⁴molecules
Condition = STP
Unknown:
Volume of gas = ?
Solution;
The volume of gas at STP is expressed below;
Volume of gas = number of moles x 22.4
Number of moles =
Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;
Number of moles of NH₃ = }{6.02 x 10^{23} }[/tex]
Number of moles of NH₃ = 12.5moles
Volume of gas = 12.5 x 22.4 = 27.9L
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Volume of gas at STP brainly.com/question/7795301
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