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tatiyna
3 years ago
7

Name the precipitate that forms when aqueous solutions of barium nitrate and potassium sulfate are mixed.

Chemistry
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

barium sulfate BaSO₄

Explanation:

When aqueous solutions of barium nitrate and pottasion sulfate are mixed, a precipitate of barium sulfate BaSO₄ forms.

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What is the concentration of HNO3 if 5.00×10−2 mol are present in 905 mL of the solution?
Zepler [3.9K]

Answer:

0.05525 M or 55.25 mM

Explanation:

Concentration = moles/volume

*Note that volume is expressed in L so you will need to convert mL > L here

C= \frac{n}{V}\\C= \frac{0.05}{0.905}\\C=0.05525

8 0
3 years ago
Consider the reaction between hcl and o2: 4hcl(g)+o2(g)→2h2o(l)+2cl2(g) when 63.1 g of hcl are allowed to react with 17.2 g of o
Roman55 [17]
The balanced chemical reaction is expressed as:

<span>4hcl(g)+o2(g)→2h2o(l)+2cl2(g)

To determine the percent yield of the reaction, we need to calculate for the theoretical yield. This is the maximum amount of the product that can be produced from the reaction given the initial amounts of the reactants. First, we identify the limiting reactant as follows:

</span><span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 1 mol O2 / 4 mol HCl) ( 32 g / mol) = 13.85 g O2 
17.2 g of o2 ( 1 mol / 32 g ) ( 4 mol HCl / 1 mol O2) ( 36.46 g / mol) =  78.39 g HCl

Therefore, the limiting reactant would be HCl. We use the value for the HCl to calculate for the theoretical yield.

</span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 2 mol Cl2 / 4 mol HCl) ( 70.9 g / mol ) = 61.35 g Cl2

Percent yield = actual / theoretical x 100
                      = 59.6 / 61.35 x 100
                      = 97.1%
4 0
3 years ago
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Answer:

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oh, and medicine

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3 years ago
How can glass be a liquid if it's so hard?​
levacccp [35]

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