Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
So first you want to draw out you triangle and label everything so side a would be x, side b would be 15 and c would be x
next the angles need to be label
and finally the anwser is 150m
Answer:
The midpoint is (2,0)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2
(5+-1)/2 =4/2 =2
To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2
(6+-6)/2 =0/2 =0
The midpoint is (2,0)
Slope = (-3 - (-15))/(-9 - (-5)) = - 12/4 = -3
Depending on the values of 'r', 't', and 'e', the numerical value of that expression
might have many factors.
For example, if it happens that r=5, t=1, and e=4 for an instant, then, just
for a moment, (r + t)(e) = (5+1)(4) = 24, and the factors of (r+t)(e) are
1, 2, 3, 4, 6, 8, 12, and 24 . But that's only a temporary situation.
The only factors of (r+t)(e) that don't depend on the values of 'r', 't', or 'e' ,
and are always good, are (<em>r + t</em>) and (<em>e</em>) .
