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Bezzdna [24]
3 years ago
15

Is the quantity of heat needed to

Chemistry
1 answer:
boyakko [2]3 years ago
6 0
D. Heat of vaporization, because the liquid is turning into a gas phase (vapor)
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___________ carry oxygen throughout the human body.
SOVA2 [1]
Red blood cells carry oxygen throughout the human body
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4 years ago
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Convert the following please
qwelly [4]

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1. 54600

3. 78740.2

Explanation:

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8 0
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The production of water proceeds according to the following equation.
dem82 [27]

Answer:

Place the reactants in a smaller container.

Explanation:

If you were to reduce the source of heat, the hydrogen and oxygen molecules would lose their kinetic energy, resulting in less collisions.

_______________________________________________________

Maintaining the same temperature of the reactants, the speed would neither increase nor decrease as temperature is directly proportional to the kinetic energy of the molecules, which in turn is directly proportional to the number of collisions. However, placing the reactants in a smaller container would result in less volume, and hence the molecules would collide with one another more often!

<u><em>Hope that helps!</em></u>

4 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
A sample of carbon dioxide has a mass of 54.0 g.
cluponka [151]

Since 1 molecule =1 mole

So 1 mole has 44grams

4 0
3 years ago
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