Answer:
Barium - Ba
Barium is a chemical element with the symbol Ba and atomic number 56. It is the fifth element in group 2 and is a soft, silvery alkaline earth metal. Because of its high chemical reactivity, barium is never found in nature as a free element.
Symbol: Ba
Atomic mass: 137.327 u
Electron configuration: [Xe] 6s2
Atomic number: 56
Van der Waals radius: 268 pm
Discoverers: Humphry Davy, Carl Wilhelm Scheele
<span><span>-When sunlight strikes a falling drop of water it is refracted, changed indirection, by the surface of the water.</span>
The light continues into the drop and is reflected from the back of the drop to the front. When the beam hits the front it is refracted again and emerges from the drop as the color spectrum that we see in a rainbow.<span>-The water drop acts like a prism to seperate the light into its different wave lengths.</span></span>
Electrons move from the potassium atoms to the sulfur atoms.
Answer:
Size of image: 1.8 cm inverted
Magnification of camera: -0.1
Explanation:
Given:
- = size of bird = 18 cm
- = distance of the bird from the camera = 2 m = 200 cm
- = distance of the film from the camera = 20 cm
Assume:
- = magnification of the camera
- = size of image of the bird
Using sign convention, we have
The hole in the pinhole camera behaves as a convex lens. The other face opposite to the hole face behaves like a film where the image is formed to be seen. So, using the formula of magnification, we have
This means the image of the bird measures 1.8 cm in length where negative sign in the calculation represents that the image formed is inverted.
Hence, the image of the bird on the film is 1.8 cm large.
Now, again using the formula of magnification, we have
Hence, the magnification of the camera is -0.1.
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So
We have to find the speed of the wave in the string
Speed is equal to
So speed of the wave in the string will be 3.2 m/sec