A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 850 N/C. The change in the electric potential energy of the proton-field system when the proton travels to x = 2.50m is -3.40 × 10⁻¹⁶ J (Option B)
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How is the change in electric potential energy of the proton-field system calculated?</h3>
- Work done on the proton =Negative of the change in the electric potential energy of the proton field
- In the given case, W = -qΔV
- -W = qΔV
- = qEcosθ
- Therefore, work done on the proton = -e(8.50×
N/C)(2.5m)(1) - = -3.40×
J - Any change in the potential energy indicates the work done by the proton.
- Therefore the positive sign shows that the potential energy increases when the proton does the work.
- The negative sign shows that the potential energy decreases when the proton does the work.
To learn more about electric potential energy, refer
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Hence,
<span>∆H = ∆U + W </span>
<span>=> </span>
<span>W = ∆H - ∆U </span>
<span>= -5074 kJ - (-5084.) kJ </span>
<span>= 10 kJ</span>
Answer:
110 g
Explanation:
q = mCΔT
where q is heat, m is mass, C is specific heat capacity, and ΔT is change in temperature.
Given q = 250 J, C = 0.228 J/g/°C, and ΔT = 10.0 °C:
250 J = m (0.228 J/g/°C) (10.0 °C)
m = 110 g
Answer:
These findings led to the formation of the modern cell theory, which has three main additions: first, that DNA is passed between cells during cell division; second, that the cells of all organisms within a similar species are mostly the same, both structurally and chemically; and finally, that energy flow occurs within.
Explanation:
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