Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m
Answer:
(a) Fₓ = 0 N
= 9.08 N
(b)
(a) Fₓ = 0 N
<u></u>
= 9.08 N
(c)
= 0 N
Fₓ = 9.08 N
Explanation:
The magnitude of the force will remain the same in each case, which is given as follows:
F = ma (Newton's Second Law)
where,
F = force = ?
m = mass = 4.54 kg
a = acceleration = 2 m/s²
Therefore,
F = (4.54 kg)(2 m/s²)
F = 9.08 N
Now, we come to each scenario:
(a)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be positive:
<u></u>
<u> = 9.08 N</u>
<u></u>
(b)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be negative:
<u></u>
<u> = - 9.08 N</u>
<u></u>
(c)
Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:
<u></u>
<u> = 0 N</u>
<u>Fₓ = 9.08 N</u>
Usually start on the internet, there is bound to be something or a form of information on it.
The variable you can change in an experiment is ( B ) A dependent variable
Use newton's second law, F = ma.
Force is 34 N and a is 4 m/s/s
34 = m(4), solve for m.
34/4 = 8.5 g