Best Answer: Ionic binary compounds -- contain a metal cation and an anion made of a nonmetal or a polyatomic anion. Consider calcium phosphate:
Ca = 2+ (Group IIA)
PO4 = 3- (phosphate)
The lowest common multiple of 2+ and 3- is 6. You must have 3 Ca2+ to make +6; you must have 2 PO43- to make -6. The sum of the positive and negative charges must be equal in a compound because they are electrically neutral.
Ca3(PO4)2 -- calcium phosphate
Binary molecular compounds -- contain two or more nonmetals bonded covalently. There are no ions present because the atoms share electrons. Prefixes are used to indicate the number of atoms of each kind present. Examples are:
SO2 -- sulfur dioxide
N2O4 -- dinitrogen tetraoxide
PCl3 -- phosphorous trichloride
CO -- carbon monoxide
The general formula for an acid is HX, where X is an anion. Binary acids contain H and a nonmetal and are named with the prefix "hydro" and the suffix "ic". Examples are:
HCl -- hydrochloric acid
H2S -- hydrosulfuric acid
HF -- hydrofluoric acid
Ternary acids contain H and a polyatomic anion. Examples are:
H2SO4 -- sulfuric acid
HNO3 -- nitric acid
HNO2 -- nitrous acid
HClO3 -- chloric acid
HClO2 -- chlorous acid
HClO -- hypochlorous acid
The names of the anions are changed as follows:
-ate anions form -ic acids
-ite anions form -ous acids
per...ate anions form per...ic acids
hypo...ite anions form hypo...ous acids.
Answer : The molar heat of solution of KCl is, 17.19 kJ/mol
Explanation :
First we have to calculate the heat of solution.
where,
q = heat produced = ?
c = specific heat capacity of water = 
= change in temperature = 0.360 K
Now put all the given values in the above formula, we get:
Now we have to calculate the molar heat solution of KCl.
where,
= enthalpy change = ?
q = heat released = 460.8 J
m = mass of 
= 2.00 g
Molar mass of = 74.55 g/mol
Now put all the given values in the above formula, we get:
Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol
Answer:
The specific heat of the metal is 2.09899 J/g℃.
Explanation:
Given,
For Metal sample,
mass = 13 grams
T = 73°C
For Water sample,
mass = 60 grams
T = 22°C.
When the metal sample and water sample are mixed,
The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.
Since, heat lost by metal is equal to the heat gained by water,
Qlost = Qgain
However,
Q = (mass) (ΔT) (Cp)
(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)
After mixing both samples, their temperature changes to 27°C.
It implies that
, water sample temperature changed from 22°C to 27°C and metal sample temperature changed from 73°C to 27°C.
Since, Specific heat of water = 4.184 J/g°C
Let Cp be the specific heat of the metal.
Substituting values,
(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)
By solving, we get Cp =
Therefore, specific heat of the metal sample is 2.09899 J/g℃.
