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Ad libitum [116K]
4 years ago
5

Which of these is a base? a-vinegar b-ammonia c-HCl d- HNO3

Chemistry
2 answers:
Lady_Fox [76]4 years ago
6 0
B- ammonia. ammonia has a pH level of about 11, and anything higher than 7  is more basic and anything less than 7 is more acidic. 7 is considered neutral.
valkas [14]4 years ago
5 0

Answer:

ammonia

Explanation:

ammonia is a base because it has a pH of about 11, and anything with a pH lower higher 7 is a base. also, i took the test and got it right. hope this helps!

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Calcium oxide (CaO) can react with carbon dioxide (CO2) in a synthesis reaction. Select the most likely products of this reactio
ser-zykov [4K]

Answer: CaCO3 reaction.

Explanation: CaO and  combine together to result in the formation of calcium carbonate compound. we know it is a synthesis reaction.so we can conclude that the most likely products of Cao + co2 → CaCO3 reaction.

6 0
2 years ago
Which order shows decreasing wavelength?
blagie [28]

Answer:

The answer is c radio --> infrared --> ultraviolet --> gamma

Explanation:

I just did it

4 0
3 years ago
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Na has a lower IE1 than Mg, but Mg has a lower IE2 than Na because: The radius of Na is smaller than that of Mg. IE1 increases f
kotegsom [21]

Answer:

Explanation: IE1 increases from left to right across a period. However, since Na has only one valence electron, IE2 for Na involves the removal of a core electron − requiring significantly more energy.

7 0
3 years ago
What must be conserved in a balanced nuclear equation?
Law Incorporation [45]
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5 0
4 years ago
For the oxidation of glucose C6 H12 O6 + 602 -- 6H2O + 6C02, How many moles of oxygen will it take to consume 3.9 moles of gluco
Mamont248 [21]

Answer:

The answer to your question is 23.4 moles of Glucose

Explanation:

Data

moles of Oxygen = ?

moles of glucose = 3.9

-Balanced chemical reaction

           1C₆H₁₂O₆  +  6O₂   ⇒   6H₂O  +  6CO₂

Process

1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.

           1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂

    3.9 moles of C₆H₁₂O₆ ------------------   x

                                  x = (3.9 x 6 ) / 1

                                  x = 23.4 moles

2.- Conclusion

3.9 moles of glucose consume 23.4 moles of oxygen

5 0
4 years ago
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