Answer: 19 dollar fortnite card Explanation:who wants it
Answer:
d= 14.007 amu
Explanation:
Abundance of N¹⁴ = 99.63%
Abundance of N¹⁵ = 0.37%
Atomic mass of N¹⁴ = 14.003 amu
Atomic mass of N¹⁵ = 15.000 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100
Average atomic mass = 1395.12 + 5.55 / 100
Average atomic mass = 1400.67/ 100
Average atomic mass = 14.007 amu.
Answer:The product and reactants reach a final, unchanging level.
It was a compound, hence it needed to be separated into its individual components by chemical means.
The value of the given expression up to correct significant figures is
.
- The rule that applies for the multiplication and division is :
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
- The rule that applies for the addition and subtraction is :
The least precise number present after the decimal point determines the number of significant figures in the answer.
Given:
The expression: (23.4m)(14m)
To find:
The answer up to correct a number of significant figures.
Solution
Number of significant figures in '23.4' = 3
Number of significant figures in '14' = 22

The number with the least significant figures is '14' is 2, so the answer will be reported up to 2 significant figures:

Number of significant figures in '330' = 3
The value of the given expression up to correct significant figures is
.
Learn more about significant figures here:
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