Can someone check my work and tell me if I did it right

Gold is used for jewelry because it is malleable. This means it can be easily molded into different shapes. What is this an exam

anastassius [24]

Malleablity is a physical property so hence

D. Physical property is the answer

6 0

2 years ago

Carbon monoxide is a gas at 0 °c and a pressure of 1.58 × 105 pa. it is a diatomic gas, each of its molecules consisting of one

Hoochie [10]

Given temperature = $0^{0}C = (0^{0} + 273 )K = 273 K$

Pressure = 1.58 × $10^{5} Pa$ × $\frac{1 atm}{1.01325*10^{5}Pa}$

= 1.56 atm

$Density =\frac{PM}{RT}$

ρ = $\frac{(1.56 atm)(28.01 g/mol)}{(0.08206 L.atm/mol.K)(273 K)}$

= 1.95 g/L

5 0

3 years ago

If chromium(II) iodide is dissolved in water you can say that the equilibrium concentrations of chromium(II) and iodide ions are

jenyasd209 [6]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set up the equilibrium reaction by which chromium (II) iodide is ionized as follows:

$CrI_2(s)\rightarrow Cr^{2+}(aq)+2I^-(aq)$

Thus, it is possible to notice that the the moles, and therefore concentrations, of chromium(II) and iodide ions are going to be different, by a factor of 2 due to the mole ratio in the aforementioned chemical equation.

Regards!

7 0

3 years ago

mengapa air panas maupun air dingin yg disimpan didalam termos cenderung lebih tahan lama suhu panas atau dingin

Juliette [100K]

Un termo tiene alrededor de 2 capas de metal allí y es por eso que si hace frío, el metal hace que su Sures no caliente. que es resistente debido a las muchas capas en el termo.

8 0

2 years ago

Read 2 more answers

BRAINLIEST PLEASEEE HELPLP 5. In a lab experiment, 2.5 grams of sodium bicarbonate is heated and decomposed into

umka21 [38]

Answer:

Explanation:

Sodium bicarbonate,

NaHCO

3

, will decompose to form sodium carbonate,

Na

2

CO

3

, water, and carbon dioxide,

CO

2

NaHCO

3(s]

→

Na

2

CO

3(s]

+

CO

2(g]

+

H

2

O

(g]

Notice that you have a

2

:

1

mole ratio between sodium bicarbonate and sodium carbonate. This means that the reaction will produce half as many moles of the latter than whatever number of moles of the former underwent decomposition.

Use sodium carbonate's molar amss to determine how many moles you'd get in that sample

0.685

g

⋅

1 mole NaHCO

3

84.007

g

=

0.008154 moles NaHCO

3

Now, if the reaction were to have a

100

%

yield, it would produce

0.008154

moles NaHCO

3

⋅

1 mole Na

2

CO

3

2

moles NaHCO

3

=

0.004077 moles Na

2

CO

3

Use the molar mass of sodium carbonate to determine how many grams would contain this many moles

0.004077

moles

⋅

105.99 g

1

mole

=

0.4321 g Na

2

CO

3Sodium bicarbonate,

NaHCO

3

, will decompose to form sodium carbonate,

Na

2

CO

3

, water, and carbon dioxide,

CO

2

NaHCO

3(s]

→

Na

2

CO

3(s]

+

CO

2(g]

+

H

2

O

(g]

Notice that you have a

2

:

1

mole ratio between sodium bicarbonate and sodium carbonate. This means that the reaction will produce half as many moles of the latter than whatever number of moles of the former underwent decomposition.

Use sodium carbonate's molar amss to determine how many moles you'd get in that sample

0.685

g

⋅

1 mole NaHCO

3

84.007

g

=

0.008154 moles NaHCO

3

Now, if the reaction were to have a

100

%

yield, it would produce

0.008154

moles NaHCO

3

⋅

1 mole Na

2

CO

3

2

moles NaHCO

3

=

0.004077 moles Na

2

CO

3

Use the molar mass of sodium carbonate to determine how many grams would contain this many moles

0.004077

moles

⋅

105.99 g

1

mole

=

0.4321 g Na

2

CO

3

6 0

3 years ago