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dimulka [17.4K]
3 years ago
10

Simplify (x^a.x^b)^a-b*(x^b.x^c)^b-c*(x^c.x^a)^c-astep by step..

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)

vaieri [72.5K]3 years ago
6 0

Answer:

x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)

Hope it helped!

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PLEASE ANSWER ASAP!! WILL GIVE 50 POINTS! AND BRAINLIST!
levacccp [35]

\frac{3}{5}  -  \frac{1}{4}  =  \frac{7}{20}
then
\frac{7}{20}  \div  \frac{7}{10}  =  \frac{1}{2}
4 0
3 years ago
Can someone please explain to me how to do this
muminat

Step-by-step explanation:

u should:

7t = t + 48 » 7t - t = 48 » 6t = 48 » t = 8

and another one is:

2u + t + 13 = 10t + u - 44» 2u + 8 + 13 = 80 + u - 44»

» 2u + 21 = u + 36 » 2u - u = 36 - 21 » u = 15

8 0
3 years ago
5 3/2 x 3 6/7 you have 10 point to do the answer
pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0
2 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
Answer this question pls!! (Will give Brainliest)
kvasek [131]
ANSWER:
22
(All you’re doing is plugging in the values into the formula)

4 0
3 years ago
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