Answer: The common number is 26.
Step-by-step explanation:
We know that the n-th term of a sequence is:
aₙ = 3*n^2 - 1
And the n-th term of another sequence is:
bₙ = 30 - n^2
Remember that in a sequence n is always an integer number.
We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:
aₙ = bₓ
This is:
3*n^2 - 1 = 30 - x^2
Let's isolate one of the variables, i will isolate n.
3*n^2 = 30 - x^2 + 1 = 31 - x^2
n^2 = (31 - x^2)/3
n = √( (31 - x^2)/3)
Now we can try with different integer values of x, and see if n is also an integer.
if x = 1
n = √( (31 - 1^2)/3) = √10
We know that √10 is not an integer, so we need to try with another value of x.
if x = 2:
n = √( (31 - x^2)/3) = √(27/3) = √9 = 3
Then if we have x= 2, n is also an integer, n = 3.
Then we have:
a₃ = b₂
The common number between both sequences is:
a₃ = 3*(3)^2 - 1 = 26
b₂ = 30 - 2^2 = 26
9 = 1 + 8x - 8
Add 8 to both sides:
17 = 1 + 8x
Minus 1 on both sides:
16 = 8x
Divide both sides by 8
2 = x
Hope it helped :)
First off, you must have a calculator to find any cos,sin, or tan.
tangent of 39 degrees is .80978
rounding to the nearest ten thousandth would be .8098 because the 8 in the hundred thousandths is greater than 5.
The sum of 5+2=7
The sum of 2+5=7
The sum is the same because basically, the position and location of the numbers do not matter in <em>addition </em>and multiplication. However, the position matters in subtraction and division.
Hope that helps!
Answer:
thats a cone
Step-by-step explanation:
