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olga2289 [7]
3 years ago
12

A plumb bob is hanging from the ceiling of a car. If the car moves with an acceleration a, what is the angle made by the string

with the vertical?
Physics
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

\theta=\tan^{-1}\dfrac{a}{g}

Explanation:

Here we are assuming that the car is moving in a straight line and is traveling on a smooth surface. When the car is moving with acceleration a the bob moves in the opposite direction with the same acceleration. Gravity is acting on the bob so it is experiencing an acceleration of g downwards.

The angle between the acceleration a and the acceleration due to gravity g is

\theta=\tan^{-1}\dfrac{a}{g}.

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Sitting in a chairlift, Rebecca has a gravitational potential energy of 5,997.6
stira [4]

Answer:

B) 12 m

Explanation:

Gravitational potential energy is:

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Given PE = 5997.6 J, and m = 51 kg:

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8 0
3 years ago
A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu
kolbaska11 [484]

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

\omega f = \omega o-\alpha*t

Solving for α:

\alpha=\frac{\omega o-\omega f}{t}

where ωo = 600*2*π/60;   ωf = 0;    t=10s

\alpha=6.283rad/s^2

The sum of torque is:

\tau=I*\alpha

\tau=M*R^2/2*\alpha

\tau=0.060 N.m

8 0
3 years ago
Two point charges of equal magnitude are 8.0 cm apart. At the midpoint of the line connecting them, their combined electric fiel
bagirrra123 [75]

Answer:

r = 8/2 = 4cm = 0.04m

k = 9×10^9

Enet = 51 N/C

Enet = E1 + E2

since E1 = E2

E1 = Enet/2 = 51/2

E/2 = kq/r²

q = Er²/2k

q = (51 × 0.04²)/(2×9×10^9)

q = 4.5×10^-12 C

q1 = q2 = 4.5 pC

Explanation:

The electric field is a region around a

charge in which it exerts electrostatic force

on another charges. While the strength of

electric field at any point in space is called

electric field intensity. It is a vector

quantity. Its unit is NC¯¹.

According to coulomb’s law ,if a unit

positive charge q (call it a test charge) is

brought near a charge q (call a field

charge) placed in space,the charge q will

experience a force. The value of this force

depends upon the distance between the

two charges. If the charge q is moved

away from q ,this force would decrease till

at a certain distance the force would be

practically reduced to zero. The charge q

is then out of the influence of charge q.

The region of space surrounding the charge

q in which it exerts a force on the charge

q is known as E.F of the charge

q. Mathematically it is expressed as:

E =F/q

The direction of the vector E is the same

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positive scalar. Dimensionally,the E.F is

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newton/coulomb (N/C).

7 0
2 years ago
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