Answer:
The direction of the force at A and B is perpendicular to the walls of the container.
The direction of the force at C is down.
The direction of the force in D is up
The direction of the force at E is to the left.
The attached figure shows the forces exerted by the water at points A, B, C, D and E.
Explanation:
The water is in contact with the bowl and with the fish. It exercises at points A, B, C, D and E, but the direction is different from the force.
The fish has a buoyant force on the water and that direction is up. The direction of at point D is up.
The column of water on the fish has a downward force, therefore the direction of the force at point C is down. The water column to the right of the fish has a force to the left, and the direction at point E is to the left.
The water will exert a force on the walls of the container and this force at points A and B is a on the walls of the container.
Answer:
The separation between the two lowest levels = 
The values of n where the energy of molecule reaches 1/2 kT at 300K = 
The separation at this level = 1.8 *
J
Explanation:
Knowing the formula
En = 
Mass of oxygen molecule
m (O2) = 32 amu * 
So the energy diference between the two lowest levels:
E2 - E1 = 
E2 - E1 = 
Now we should find n where the energy of molecule reaches 1/2 kT
En =
= 
= 


by the end is necessary to calculate the separation of the level
En - En-1 = 
= 1.8 *
J
Answer:
Atoms found in nature are either stable or unstable. ... An atom is unstable (radioactive) if these forces are unbalanced; if the nucleus has an excess of internal energy. Instability of an atom's nucleus may result from an excess of either neutrons or protons
Answer:
helium-4 (90%) or tritium (7%).
Explanation:
hope it helped u buddy
Answer:
The length of line is 78 cm or 0.78 m.
Explanation:
initial reading 2 mark
final reading 80 cm
The length of the line
= final reading - initial reading
= 80 - 2
= 78 cm
1 cm = 0.01 m
So, 78 cm = 0.78 m