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Aleksandr [31]
3 years ago
10

26. The speed of light in a certain medium is

Physics
1 answer:
horrorfan [7]3 years ago
6 0

The number we need in order to answer the question belongs in the space between the words "is" and "of".  You left that blank blank, so there really isn't any question here to answer.

HOWEVER ... the refractive index of a medium can never be less than 1.0 , so we know for sure that <em>choice-a can't be</em> the correct answer.

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Pressure in a liquid increases with its ..........​
Novay_Z [31]

Answer: Pressure increases as the depth increases

Explanation: The pressure in a liquid is due to the weight of the column of water above. Since the particles in a liquid are tightly packed, this pressure acts in all directions.

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A roller coaster is going through a loop with a circular radius of 9.1 meters, how fast must the roller coaster be moving at the
Verdich [7]

Answer:

at least 20mph

Explanation:

8 0
3 years ago
Solve for x<br> –30 = 5(x + 1)
balandron [24]

Answer:

-30=5(x+1) is -7

Explanation:

distribute flip subtract 5 from both sides divide both sides by 5

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3 years ago
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At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515
Talja [164]

Complete  Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The  angle is  

Explanation:

From the question we are told that

   The light emerging from second Polaroid is 1/5 the  unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

             I_1 = \frac{I_o}{ 2 }

Generally from the Malus law the intensity of light emerging from the second Polaroid  is mathematically represented

      I_2  =  I_1 cos^2 (\theta )

=>   cos^2 (\theta ) =  \frac{I_2}{I_1 }

=>   cos (\theta) =  \sqrt{ \frac{I_2}{I_1} }

From the question I_2  =  \frac{I_o}{5}

     cos (\theta) =  \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }

     cos (\theta) =  \sqrt{ \frac{2}{5} }

=>    \theta =   cos ^{-1} [\sqrt{\frac{2}{5}}  ]

=>    \theta  =  50.77^o

8 0
3 years ago
A spider spins a web with silk threads of density 1300 kg/m3 and diameter 3.0 μm . a typical tension in the radial threads of su
Tema [17]

Answer:

Explanation:

The velocity of a wave in a string is equal to:

v = √(T / (m/L))

where T is the tension and m/L is the mass per length.

To find the mass per length, we need to find the cross-sectional area of the thread.

A = πr² = π/4 d²

A = π (3.0×10⁻⁶ m)²

A = 2.83×10⁻¹¹ m²

So the mass per length is:

m/L = ρA

m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)

m/L = 3.68×10⁻⁸ kg/m

So the wave velocity is:

v = √(T / (m/L))

v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))

v ≈ 440 m/s

The speed of sound in air at sea level is around 340 m/s.  So the spider will feel the vibration in the thread before it hears the sound.

5 0
3 years ago
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