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Lady_Fox [76]
3 years ago
9

The area of a rectangle is 77ft^2 , and the length of the rectangle is 3ft more than twice the width. What are the dimensions of

the rectangle ?
Mathematics
1 answer:
Ivan3 years ago
3 0
Area = 77 ft^2
W = W
L = 2W + 3

Area = L * W
Area = (2W + 3)*W
Area = 2W^2 + 3W
The area is also 77
So 
Area = 2w^2 + 3W = 77
Area = 2w^2 + 3W - 77 = 0
Now factor the question
77 can only factor into 1,77 which is highly unlikely and 7 and 11
As a guess I'm going to try 7. It that's true, we get
(x + 7)(2x - 11) = 0 This might work.
x^2 + 14x - 11x - 77 = 0
x^2 + 3x - 77 = 0 So the factoring is correct.

x + 7 = 0
x = - 7
2x - 11 = 0
2x = 11
x = 11/2
x = 5.5 
W = 5.5 <<<< Answer

The minus seven is meaningless.
Width = 5.5
Length = 2*5.5 + 3
Length = 11 + 3
Length = 14 <<<< answer

Now we have to check the area.
Area = L * W
Area = 14 * 5.5
Area = 77. You have a complete answer.

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Summary of even and odd functions

A function f is even if the graph of f is symmetric with respect to the y-axis. Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f.

A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

From the definition itself, we see how can we test if the functions are even or odd.

- First graph (to the left)

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- Second graph (to the right)

From the graph, we see that the function is symmetric with respect to the origin, the left side (x<0) is a reflection (along with the origin) of the side to the right (x>0), so it is an odd function.

- First function (to the left)

The function:

g(x)=5x^2

is an even function because we see that:

g(-x)=5\cdot(-x)^2=5x^2=g(x)

- Second function (to the right)

The function:

h(x)=-2x^5+3x^3

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h(-x)=-2\cdot(-x)^5+3\cdot(-x)^3=-(-2x^5+3x^3)=-h(x)^{}

Summary

We have the following results:

- First function (to the left): even

- Second graph (to the right): odd

- First function (to the left): even

- Second function (to the right): odd

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