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3 years ago

23. A satellite moving at the same velocity in space is an example of which

Chemistry

1 answer:

jolli1 [7]3 years ago

7 0

Answer:

A. LST

Explanation:

• 1st Law: The path of each planet around the Sun is an ellipse with the Sun at one focus.

• 2nd Law: The line from the Sun to any planet sweeps out equal areas of space in equal time intervals.

• 3rd Law: The square of the orbital period of a planet is directly proportional to the cube of the average distance

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If a person weighs 87lbs and has to be given a drug with a dosage of 50 milligrams per kilogram body weight, how many grams of t

Katarina [22]

Answer:

1 957,5

Explanation:

87libs=39.5kg that equals 50=1.957.5

7 0

3 years ago

Given the following reaction: 2N2O5=2N2O4+O2, if the rate of oxygen production is 0.15M/min, determine:

astraxan [27]

Answer:

a. $r_{N_2O_5}=-0.075M/min$

b. $r_{N_2O_4}=0.075M/min$

Explanation:

Hello.

In this case, according to the balanced chemical reaction, we can write the law of rate proportions:

$\frac{r_{N_2O_5}}{-2} =\frac{r_{N_2O_4}}{2} =\frac{r_{O_2}}{1}$

Thus, we proceed as follows:

a. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

$\frac{r_{N_2O_5}}{-2} =\frac{r_{O_2}}{1}\\\\r_{N_2O_5}=\frac{r_{O_2}}{-2} =\frac{0.15M/min}{-2}\\\\ r_{N_2O_5}=-0.075M/min$

b. Since the rate of oxygen production is 0.15 M/min, we can make the following setup:

$\frac{r_{N_2O_4}}{2} =\frac{r_{O_2}}{1}\\\\r_{N_2O_4}=\frac{r_{O_2}}{2} =\frac{0.15M/min}{2}\\\\ r_{N_2O_4}=0.075M/min$

Best regards!

8 0

3 years ago

How do you identify an acid from its chemical formula

Usimov [2.4K]

First find the names of the acids end in “acid”. Acid formulas have one of these forms: HX(aq) or HaXbOc then find the Ionic compounds that contain hydroxide. (OH-) , carbonate (CO32-) , or hydrogen carbonate (HCO3-) anions are basic.

7 0

3 years ago

Which of he following is a secondary alkanol?

hodyreva [135]

Answer: Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: $CH_3CH_2CH_2OH$ and $CH_3CH_2CH_2CH_2OH$

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: $CH_3CH(OH)CH_3$

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: $C(CH_3)_3OH$

Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

5 0

3 years ago

An element identity is defined by its number of

Marianna [84]

Answer:

Correct answer is A) Protons

Explanation:

I got it right on my test.

Can i get brainlyest

3 0

3 years ago