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Marta_Voda [28]
3 years ago
12

23. A satellite moving at the same velocity in space is an example of which

Chemistry
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

A. LST

Explanation:

• 1st Law: The path of each planet around the Sun is an ellipse with the Sun at one focus.

• 2nd Law: The line from the Sun to any planet sweeps out equal areas of space in equal time intervals.

• 3rd Law: The square of the orbital period of a planet is directly proportional to the cube of the average distance

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When electrons gain energy, what can they do?
beks73 [17]

B. When electrons gain energy, they have the power to move up to a higher energy level in an atom.

3 0
4 years ago
An object has a mass of 20 kg and a volume of 5 mL. What is the object's density?
e-lub [12.9K]
Good grief, this stuff got caught in a black hole somewhere. It is terribly dense.
1 mL = 1 cc under normal conditions.

d = mass / volume
m = 20 kg
v = 5 mL

d = 20kg / 5 mL
d = 4 kg / mL
d = 4 kg / cc

A <<<<answer
7 0
3 years ago
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3. In a typical titration experiment a student titrates a 5.00 mL sample of formic acid (HCOOH), a monoprotic organic acid, with
ira [324]

Answer:

2.893 x 10⁻³ mol NaOH

[HCOOH] = 0.5786 mol/L

Explanation:

The balanced reaction equation is:

HCOOH + NaOH ⇒ NaHCOO + H₂O

At the endpoint in the titration, the amount of base added is just enough to react with all the formic acid present. So first we will calculate the moles of base added and use the molar ratio from the reaction equation to find the moles of formic acid that must have been present. Then we can find the concentration of formic acid.

The moles of base added is calculated as follows:

n = CV = (0.1088 mol/L)(26.59 mL) = 2.892992 mmol NaOH

Extra significant figures are kept to avoid round-off errors.

Now we relate the amount of NaOH to the amount of HCOOH through the molar ratio of 1:1.

(2.892992 mmol NaOH)(1 HCOOH/1 NaOH) = 2.892992 mmol HCOOH

The concentration of HCOOH to the correct number of significant figures is then calculated as follows:

C = n/V = (2.892992 mmol) / (5.00 mL) = 0.5786 mol/L

The question also asks to calculate the moles of base, so we convert millimoles to moles:

(2.892992 mmol NaOH)(1 mol/1000 mmol) = 2.893 x 10⁻³ mol NaOH

7 0
3 years ago
Which of the following gases will effuse the most rapidly?
klio [65]
I would say D. Hope I helped, sorry if I didn't. :)
7 0
3 years ago
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What were the limitations of Dobereiner's classifcation?​
yawa3891 [41]

Answer:

Dobereiner could find only three triads; . i.e total of 9 elements only. However the total number of elements were more than that of those encompassed in Dobereiner's Triad

Explanation:

5 0
3 years ago
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