When electrons gain energy, what can they do?
1 answer:
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Answer:
The answer to your question is: 2 grams of methane
Explanation:
Data
V = 9.15 l
P = 1.77 atm
T = 57° C = 330 °K
Ar mass = 19 g
CH4 mass = ?
Formula
PV = nRT
Process
n = 0.6
Argon
40 g of Ar -------------------- 1 mol
19 g --------------------- x
x = 0.475 mol of Ar
moles of CH4 = 0.6 - 0.475
= 0.125
Methane
16 g of CH4 --------------- 1mol
x ---------------- 0.125 mol
x = 2 grams
At equilibrium the concentrations of:
[HSO₄⁻] = 0.10 M;
[SO₄²⁻] = 0.037 M;
[H⁺] = 0.037 M;
There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.
HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.
R ⇄
I
C
E
×
for
. As a result,
is large. It is no longer valid to approximate that
at equilibrium is the same as its initial value.
×
×
Solving the quadratic equation for since
represents a concentration;
Then, round the results to 2 significant figure;
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