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kumpel [21]
3 years ago
8

HELP MEEEEEEEEEEEE PLZ

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

The first 25 prime numbers (all the prime numbers less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

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Please help thank you
kompoz [17]

Answer:

Step-by-step explanation:

Jared wrote the equation as,

k + (k + 1) + (k + 2) = 4k

Solution for k will be,

3k + 3 = 4k

4k - 3k = 3

k = 3

For k = 3, consecutive numbers will be → 3, 4, 5

Jared did not get the correct answer.Solution to this equation is k = 3, giving 3, 4, and 5 as three integers. However,  3 and 5 are not even integers. He should have used the equation k + (k + 2) + (k + 4) = 4k, which gives k = 6 and the correct answer is 6, 8, 10.

3 0
3 years ago
Ek=1/2mv^2 solve for v
Mandarinka [93]

Answer: it's a '40.0-kg object, not a 40.4-kg object, which would explain why the answer is different.


Step-by-step explanation:


6 0
3 years ago
17.5=7x. X=<br> What is x
Vera_Pavlovna [14]
This is your answer ok x=2.5

3 0
3 years ago
(7^2)^4= n^8 solve for n
S_A_V [24]

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

4 0
3 years ago
Can anyone solve the system using the elimination method (TIMED)<br> 3x-5y=7<br> 2x-3y=6
steposvetlana [31]

Answer:

Hopefully help

Step-by-step explanation:

the answer in the picture

8 0
3 years ago
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