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Hunter-Best [27]
3 years ago
7

Can someone help me? please

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0

Answer:

I can but not willing right now so sorry

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Maurinko [17]
Ive never seen a question lie this before
Since the first figure is a square I guess it stand for x^2
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and finally -3 + 1 = - 2
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Option b

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Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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saveliy_v [14]

Answer:

Step-by-step explanation:

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Colt1911 [192]

Answer:

The outlier on the the scatter plot is point L(6,2).

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M(3,3)

P(5,5)

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L(6,2)

Other points are : (1,3), (2,3), (2,4), (3,4), (3,5), (4,5), (4,6), (5,6)

Now, To find the outliers on the scatter plot we plot all the given points on the graph.

The resultant graph is attached below :

An outlier is a value in a data set that is very different from the other values. That is, outliers are values which are usually far from the middle.

As we can see the graph the point L(6,2) is the most unusual or the farthest point on the scatter plot as compared with all the other points on the scatter plot.

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