Gravity
Explanation:
The unpowered cars as shown gets their potential energy from their acceleration due to gravity and the height above the ground of the hill.
Potential energy is the energy due the position or a body. It is energy primarily at rest of a body.
Potential energy = m x g x h
Where:
m = mass
g = acceleration due to gravity
h = height of the hill.
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Answer:
201.73g
Explanation:
From the chemical reaction above, it can be seen that 3 moles of hydrogen yielded 2 moles of ammonia.
Now, 17.8 moles of hydrogen will yield a certain number of moles of ammonia. To get this certain number of moles: we have (17.8 * 2)/3 = 11.87 moles
Hence, 17.8 moles of hydrogen will produce 11.87 moles of ammonia. Now, we proceed to calculate the mass of ammonia produced.
The mass of ammonia produced is the molar mass of ammonia multiplied by the number of moles of ammonia.
The molar mass of ammonia is 14 +3(1) = 17g/mol
Now the mass produced is thus 17 * 11.87 = 201.73g
<u>Answer:</u> For the given equation, only iron has the value of 
equal to 0 kJ.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f%28reactant%29%5D)
For the given chemical reaction:
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28Fe%28s%29%29%7D%29%2B%283%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%5D-%5B%283%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO%28g%29%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28Fe_2O_3%28s%29%29%7D%29%5D)
The enthalpy of formation for the substances present in their elemental state is taken as 0.
Here, iron is present in its elemental state which is solid.
Hence, for the given equation, only iron has the value of equal to 0 kJ.
Answer:
Doubling the volume of the reaction vessel and adding more oxygen to the reaction vessel will change the concentrations and will affect equilibrium concentrations.
Explanation:
Answer:
nonofur bisnuse
Explanation:
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