Write an expression for the sequence of operations described below.
2 answers:
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Answer:
a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4
b.p=0.0026,total defects=2.6
c.Less of the items produced will be classified as defects.
Step-by-step explanation:
a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.
Total defects=Production*Probability
=0.3174*1000
b.
therefore:-
Defects=Probability*Production
=0.0026*1000
=2.6
c.Reducing process variation results in a significant reduction in the number of unit defects.