Fe+CuSO4⟶Cu+FeSO4
Given that
FeSO4 = 92.50 g
Number of moles = amount in g / molar mass
=92.50 g / 151.908 g/mol
=0.609 moles FeSO4
Now calculate the moles of CuSO4 as follows:
0.609 moles FeSO4 * 1 mole CuSO4 /1 mole FeSO4
= 0.609 moles CuSO4
Amount in g = number of moles * molar mass
= 0.609 moles CuSO4 * 159.609 g/mol
= 97.19 g CuSO4
Answer:
Im pretty sure its 2 How elements are joined in the compound
Explanation:
Answer:
The correct option is;
D)
Explanation:
The given reaction is presented as follows;
NH₄Cl (s) → NH₃ (g) + HCl (g) ΔH° = 176 kJ/mol, ΔS° = 0.285 kJ/(mol·K)
We note that the Gibbs free energy, ΔG° is represented by the following equation;
ΔG° = ΔH° - T·ΔS°
Where:
T = Temperature (Kelvin)
The reaction will be spontaneous for exergonic reactions, ΔG° < 0 and it will not be spontaneous for endergonic reaction, ΔG° > 0
At room temperature, T = 25 + 273.15 = 298.15 K
Which gives;
ΔG° = 176 - 298.15 × 0.285 = 91.03 kJ/mol which is > 0 Not spontaneous reaction
At 800°C, we have;
T = 273.15 + 800°C + 1073.15 K
ΔG° = 176 - 1073.15 * 0.285 = -129.85 kJ/mol which is < 0 the reaction will be spontaneous
The correct option is therefore, that at room temperature, the reaction is not spontaneous. However, at high temperatures. like 800 °C, the free energy value turns negative and this reaction becomes spontaneous.
