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3 years ago

6

Bài 5: Một electron di chuyển được đoạn đường 1cm, dọc theo một đường sức điện, dưới tác dụng của lực điện trong một điện trường

đều có cường độ điện trường 1000V/m. Tính công của lực điện. Biết điện tích của e là – 1,6.10-19C

1 answer:

eimsori [14]3 years ago

7 0

Explanation:

guy thy guy thy guy thy guy thy guy thy

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A car moves in a straight line at a speed of 68.5 km/h. How far (in km) will the car move in 5.45 minutes at this speed?

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3 years ago

X rays of wavelength 0.0100 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr

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Answer:

a) $=4.84*10^{-12}$

b) $= -2.76*10^{-14} J$

c) $i.e -2.76*10^{-14} J$

d)= 0 and the direction of motion is equal to zero

Explanation:

a) compton shift

$\Delta\lambda = \frac{h}{mc} (1-cos\theta)$

$\Delta\lambda = \frac{6.626*10^{-34}}{9.11*10^{-11}3*10^8} (1-cos180)$

$=4.84*10^{-12}$

b) the new wavelength

$\lambda' = 10.0*10^{-12} +4.84^10^{-12}$

$=14.84*10^{-12} m$

$\Delta E = E' - E$

$=hc[\frac{1}{\lambda'}-\frac{1}{\lambda}]$

$\Delta E = 6.626*10^{-34}*(3*10^8)[\frac{1}{14.84*10^{-12}}-\frac{1}{4.8*10^{-12}}]$

$= -2.76*10^{-14} J$

C)By conservation of energy, the kinetic energy of recoiling electron is equal to the magnitude of energy between the photon energy

$i.e -2.76*10^{-14} J$

d) the angle between the positive direction of motion

$sin\phy = \frac{\lambda_t sin\theta}{\lambda'}$

$=\frac{2.43*10^{-12}sin180}{14.84*10^{-12}}$

= 0

the direction of motion is equal to zero.

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4 years ago