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2 years ago

2.50 g of Zn is added to 5.00 g of HCl

Chemistry

1 answer:

Debora [2.8K]2 years ago

5 0

Zn+2HCl ----> 2ZnCl2 + H2

For 2.50 g of Zn

Mass per mol = 2.50/molar mass of Zn = 2.50/65.38 = 0.0382 g/mol
There are two moles of ZnCl2 and total mass = 2*0.0382*molar mass of ZnCl2 = 2*0.0382*136.286 = 10.42 g

For 2 g of HCl

Mass per mol = 2/2*molar mass of HCl = 2/ (2*36.46) = 0.0274 g/mol
For the two moles of ZnCl2, mass produced = 2*0.0274*136.286 = 7.48 g

It can be noted that 2 g of HCl produced less amount of ZnCl and thus it is the limiting reagent.

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If 5,800 j of energy are applied to a 15.2 kg piece of lead, by how much does the temp change if the specific heat of lead is 0.

scoray [572]

Answer:

The answer will be 2.98K

Explanation:

Using the formula:

Q = mc∆T

Q= 5,800 (heat in joules)

m= convert 15.2kg to g which is 15200g (mass in grams)

c= 0.128 J/g °c (Specific heat capacity)

∆T= what we need to find (temperature change)

5800J = 15200g x 0.128 x ∆T

= 2.98K

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3 years ago

What is SO2 shape name?

muminat

Answer:Molecular Formula SO2

Hybridization Type sp2

Bond Angle 119o

Geometry V-Shaped or Bent

Explanation:

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3 years ago

Si 100 monedas tienen una masa total de 226.13g. Cual es la masa de una moneda

galben [10]

The mass of a coin : 2.2613 g

<h3>Further explanation </h3>

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

1. phrases

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

2. variables

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

3. constants

is a fixed value, can be a number

4. arithmetic operations ⇒ +, - , : , x

<em>If 100 coins have a total mass of 226.13g. What is the mass of a coin</em>

We can make this statement in the form of an algebraic equation :

100 coins=226.13 g

then the mass of a coin :

$\tt \dfrac{1}{100}\times 226.13~g=2.2613~g$

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2 years ago

What is the % composition of Carbon in Chromium (iii) Carbonate

photoshop1234 [79]

Step 1 - Discovering the ionic formula of Chromium (III) Carbonate

Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):

$Cr^{3+}+CO^{2-}_3\rightarrow Cr_2(CO_3)_3$

Step 2 - Finding the molar mass of the substance

To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.

The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:

$\begin{gathered} C\rightarrow3\times12=36 \\ \\ O\rightarrow9\times16=144 \\ \\ Cr\rightarrow2\times52=104 \end{gathered}$

The molar mass will be thus:

$M=36+104+144=284\text{ g/mol}$

Step 3 - Finding the percent composition of carbon

As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:

$\begin{gathered} 284\text{ g/mol ---- 100\%} \\ 36\text{ g/mol ----- x} \\ \\ x=\frac{36\times100}{284}=\frac{3600}{284}=12.7\text{ \%} \end{gathered}$

The percent composition of Carbon is thus 12.7 %.

8 0

1 year ago

What geological processes form natural gas

Ivan

Decomposed organic matter ,mud,silt ,and sand

5 0

3 years ago