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Lubov Fominskaja [6]
3 years ago
15

A gas at a pressure of 360 torrs and a volume of 750 ml. If the pressure becomes 1.5 atm what is the new volume?

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

V₂ = 236.84 mL

Explanation:

The relation between pressure and volume is inverse.

We can write it as follows :

P_1V_1=P_2V_2

We have,

P₁ = 360 torrs, V₁ = 750 mL, P₂ = 1.5 atm = 1140 torr.

So,

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{360\times 750}{1140}\\\\V_2=236.84\ mL

So, the new volume of the gas is 236.84 mL.

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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

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Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0
3 years ago
What is the percentage of hydrogen in c2h4
jarptica [38.1K]

Ethylene- C2H4 = 85.7% Carbon and 14.3% Hydrogen


Find the atomic masses for each element and multiply it by the number of atoms in the compound, then add.


C- 12.0 * 2= 24.0


H- 1.00 * 4= 4.00


-----------------------


28.0


Take the masses for each element and divide it by the total mass. Then change the answer to get the percent.


C 24.0 / 28.0= .857 = 85.7%


H 4.00 / 28.0= .143 = 14.3%


<h3>Ethylene is 85.7% Carbon and 14.3% Hydrogen </h3>
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