Answer:
First, balance the half-reactions
Second, equalize the electrons
Third,add two reaction equations to get final answer
Explanation:
For example
H₂C₂0₄ + MnO⁻₄ ---------->CO₂+Mn²⁺
(i) Balancing the half reactions
H₂C₂O₄-------->2CO₂+2H⁺+2e⁻
5e⁻ +8H⁺+MnO₄⁻----------->Mn²⁺+4H₂O
(ii)
Equalizing the electrons
5H₂C₂O₄--------->10CO₂+10H⁺+10e⁻  ---here there is a factor of 5
10e⁻+16H⁺+2MnO₄⁻--------->2Mn²⁺+8H₂O -----here there is a factor of 2
(iii)
Add the two where electrons and some Hydrogen ions will cancel out
5H₂C₂O₄+6H⁺+2MnO₄⁻---->10CO₂+2Mn²⁺+8H₂O
 
        
             
        
        
        
Answer : (C) Hafnium is the most likely identity of the given substance.
Solution :  Given, 
Mass of given substance (m) = 46.9 g
Volume of given substance (V) = 3.5 
First, find the Density of given substance.
Formula used :     

Now,put all the values in this formula, we get
 = 13.4 g/
 = 13.4 g/
So, we conclude that the density of given substance (13.4 g/ ) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/
) is approximately equal to the density of Mercury and Hafnium (13.53 and 13.31 g/ respectively).
 respectively). 
According to the question the substance is solid at room temperature but Mercury is liquid at room temperature. So, Mercury is not identical to the given substance.
Another element i.e, Hafnium is the element whose density is approximately equal to the given substance and also solid at room temperature. And we know that the melting point of solid is high.
So, Hafnium is the most likely element which is the identity of the given substance.
 
        
                    
             
        
        
        
Answer:
Digestion of food. 
Explanation:
I hope my answer help you. 
 
        
                    
             
        
        
        
Answer:
The correct answer is (b)
Explanation:
Charles law describes the behavior of gases when heated. Charles law states that the volume of a given mass of gas would increase as its Kelvin temperature increases provided the pressure is held constant. That is the volume of a given mass of gas is directly proportional to its Kelvin temperature at constant pressure
 
        
             
        
        
        
You would know that the variable is quantitative if it shows any number to express the quantity. For example, quantitative variables are 50°C, 5 atm, 2 moles, 100 L and so on. A variable is qualitative if it expresses a relative quantity but not expressing a number. Examples would be: few, too hot, several, or even describing the characteristics of a variable. Hence, when the variable is in grams, then that would be quantitative.