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4 years ago

The motion of an object parallel to the earth's surface is

Physics

1 answer:

AnnyKZ [126]4 years ago

8 0

LAWS OF MOTION:

The motion of an object parallel to the earth's surface is: Horizontal

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Are you aware of human rights violations happening in your community? Explain.

MA_775_DIABLO [31]

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Answer: We should be aware of human rights violation happening in our community. In our community, there are so many people who cannot practice their own religion and rituals. ... In many nations around the globe, domestic violence is another disadvantage in our society and another example of "human rights violations".

Explanation:

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4 years ago

Find the frequency of a spring block system if it is doing 4 oscillation in 100s

Paha777 [63]

Answer:

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F=cycles/sec

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3 years ago

What is the mass of the cube Density is 40 g/cm3 Length of the side= 2 cm

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3 years ago

How is the direction of current defined by convention

ddd [48]

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3 years ago

Need help!!! Physics due tomorrow help, help ,help

Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

$F_{net}=F_{1}-F_{2}=26-8=14N$

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

$F_{x}=Fsin ($ θ $)= 67sin(73)=64N$

then, as Q(1),

$F_{net}=F_{1}-F_{2}=64-33=31 N$

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

$F_{Tension}=420 N$

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

$F_{x}=Fsin ($ θ $)= 600sin(45)=424.264N$

$F_{y} = F sin ($ θ $)= 600cos45)=424.264N$

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

$F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N$ in east

$F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N$ in south

The total net force for perpendicular forces is calculated from the relation:

$F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N$

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = $tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}$

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, $F_{right}=F_{left}=55N$

7 0

4 years ago