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Vlada [557]
2 years ago
5

The graph represents the reaction 3H2 + N2 2NH3 as it reaches equilibrium. Based on the graph, which two statements about this r

eaction are true?
PLEASE NO LINKS OR DOWNLOADS ​

Physics
1 answer:
nata0808 [166]2 years ago
8 0

Answer:A and C

Explanation: I took the test lol

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Describe how to make a position-time graph.
salantis [7]

Answer:

There's a video called Drawing Position vs Time Graphs made by MrDGenova that may help you, it's only three minutes long.

Explanation:

Hope that helps, if not, you could tell me what you don't understand and I could try explaining it in further detail.

3 0
3 years ago
The wavelength of red helium-neon laser light in air is 632.8 nm.(a) What is its frequency?(b) What is its wavelength in glass t
inn [45]

(a) 4.74 \cdot 10^{14}Hz

The frequency of a wave is given by:

f=\frac{v}{\lambda}

where

v is the wave's speed

\lambda is the wavelength

For the red laser light in this problem, we have

v=c=3\cdot 10^8 m/s (speed of light)

\lambda=632.8 nm=632.8\cdot 10^{-9} m

Substituting,

f=\frac{3\cdot 10^8 m/s}{632.8 \cdot 10^{-9} m}=4.74 \cdot 10^{14}Hz

(b) 427.6 nm

The wavelength of the wave in the glass is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 = 632.8\cdot 10^{-9} m is the original wavelength of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

\lambda=\frac{632.8\cdot 10^{-9}m}{1.48}=427.6\cdot 10^{-9}m=427.6 nm

(c) 2.02\cdot 10^8 m/s

The speed of the wave in the glass is given by

v=\frac{c}{n}

where

c = 3\cdot 10^8 m/s is the original speed of the wave in air

n = 1.48 is the refractive index of glass

Substituting into the formula,

v=\frac{3\cdot 10^8 m/s}{1.48}=2.02\cdot 10^8 m/s

5 0
3 years ago
Select the correct answer. Which statement is true about a polarized object? A. It gains electrons and becomes negatively charge
coldgirl [10]

Answer:

C. The number of positive and negative charges can be the same.

Explanation:

3 0
3 years ago
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
weeeeeb [17]

Complete Question

A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.

Answer:

The value v_2  =  4 \sqrt{10} \  m/s

Explanation:

From the question we are told that

   The  charge on the first sphere is  q_1  =  2\mu C  =  2*10^{-6} \  C

    The charge on the second sphere is  q_2 =  8 \mu C = 8*10^{-6} \  C

     The  mass of the second charge is m  =  1.50 \  g  =  1.50 *10^{-3} \ kg

      The  distance apart is  d =  0.4 \  m

      The  speed of the second  sphere is  v_1  =  20 \  ms^{-1}

Generally the total energy possessed by when q_2 and  q_1 are separated by 0.8 \  m is mathematically represented

     Q =  KE + U

Here KE   is  the kinetic energy which is mathematically represented as

     KE  =  \frac{1 }{2}  m (v_1)^2

substituting value

     KE  =  \frac{1 }{2}  * ( 1.50 *10^{-3}) (20 )^2

     KE  =  0.3 \  J

And  U is  the  potential  energy which is mathematically represented as

        U  =  \frac{k *  q_1 *  q_2  }{d }

substituting values

       U  =  \frac{9*10^9 *  2*10^{-6} * 8*10^{-6}  }{0.8 }

      U  =  0.18 \  J

So

       Q =  0.3 +  0.18

       Q =  0.48 \  J

Generally the total energy possessed by when q_2 and  q_1 are separated by 0.4 \  m is mathematically represented

         Q_f =  KE_f + U_f

Here KE_f is  the kinetic energy which is mathematically represented as

     KE_f  =  \frac{1 }{2}  m (v_2^2

substituting value

     KE_f  =  \frac{1 }{2}  * ( 1.50 *10^{-3}) (v_2 )^2

     KE_f  =  7.50 *10^{ -4} (v_2 )^2

And  U_f is  the  potential  energy which is mathematically represented as

        U_f  =  \frac{k *  q_1 *  q_2  }{d }

substituting values

       U_f  =  \frac{9*10^9 *  2*10^{-6} * 8*10^{-6}  }{0.4 }

      U_f  =  0.36 \  J

From the law of energy conservation

     Q =  Q_f

So

    0.48 =  0.36 +(7.50 *10^{-4} v_2^2)

   v_2  =  4 \sqrt{10} \  m/s

     

   

6 0
3 years ago
How to calculate moments with 3 separate weights of different amounts at different points?
Rina8888 [55]
I don't completely understand your drawing, although I can see that you certainly
did put a lot of effort into making it.  But calculating the moment is easy, and we
can get along without the drawing.

Each separate weight has a 'moment'.
The moment of each weight is: 

             (the weight of it) x (its distance from the pivot/fulcrum) .

That's all there is to a 'moment'.

The lever (or the see-saw) is balanced when (the sum of all the moments
on one side) is equal to (the sum of the moments on the other side).

That's why when you're on the see-saw with a little kid, the little kid has to sit
farther away from the pivot than you do.  The kid has less weight than you do,
so he needs more distance in order for his moment to be equal to yours.
6 0
3 years ago
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