Answer : The mass of ammonia produced can be, 121.429 k
Solution : Given,
Mass of 
 = 100 kg  = 100000 g
Mass of 
 = 100 kg = 100000 g
Molar mass of 
 = 28 g/mole
Molar mass of 
 = 2 g/mole
Molar mass of 
 = 17 g/mole
First we have to calculate the moles of 
 and 
.


Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 1 mole of 
 react with 3 mole of 
So, 3571.43 moles of 
 react with 
 moles of 
From this we conclude that, 
 is an excess reagent because the given moles are greater than the required moles and 
 is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of 
From the reaction, we conclude that
As, 1 mole of 
 react to give 2 mole of 
So, 3571.43 moles of 
 react to give 
 moles of 
Now we have to calculate the mass of 


Therefore, the mass of ammonia produced can be, 121.429 kg