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olasank [31]
3 years ago
10

Which separation techniques will you apply for the separation of the following? a) oil from water b) kerosene and petrol c) salt

from sea water d) camphor from salt ii). State the principle of chromatography.
Chemistry
1 answer:
REY [17]3 years ago
7 0

Answer:

A) Separating funnel method

B) Simple Distillation

C) Evaporation

D) Sublimation

E) It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

Explanation:

A)

B) Kerosene and petrol are both miscible liquids and the difference in their boiling point temperature is not more than 25°C. Thus, we make use of Simple distillation.

C) Can be separated by evaporation where the water is boiled and it evaporates and leaves the salt behind

D) To separate camphor from salt, we use sublimation so the camphor can change directly from solid to the gas state without passing through the liquid state.

E) Chromatography is used to separate components of a mixture.

It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

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It is a homogeneous mixture because you cannot see the individual components that make up the iced tea (such as the water, the molecules found in the tea leaves, etc.). Iced tea with ice in it is considered a heterogeneous mixture because you can distinguish the tea from the ice.
3 0
3 years ago
I am running a reaction that creates 138 grams of sulfur trioxide (S03). My theoretical yield was 156 grams. What is my percenta
alex41 [277]

Answer:

88.46%

Explanation:

Percentage yield is actual/theoretical * 100

138/156 * 100 = 88.4615385

5 0
3 years ago
What ways in which you can provide energy for your home from renewable sources
Firlakuza [10]

Answer:

Rooftop Solar Panels, Wind Turbines, Solar Oven, Hydro Power, Solar Water Heating, and Solar Air Conditioning.

Explanation:

6 0
3 years ago
Read 2 more answers
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. Identify the group 2 metal
andrey2020 [161]

5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.

According to question 5 moles of binary group 2 metal oxide mass =521  g

So, 1-mole metal oxide mass will be =521 / 5=104.2 g

Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1

So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g

Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm

So, the formula of metal oxide is SrO

The group two metal here is Sr which is strontium and lies in the same group as calcium.

To learn more about group 2 metals, visit:

brainly.com/question/18328178

#SPJ9

4 0
2 years ago
A student uses a calorimeter to determine the enthalpy of dissolving for ammonium nitrate. The student fills a calorimeter with
ale4655 [162]
Enthalpy change during the dissolution process = m c ΔT,

here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
                                                                                 = -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)

Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>

7 0
3 years ago
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