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olasank [31]
3 years ago
10

Which separation techniques will you apply for the separation of the following? a) oil from water b) kerosene and petrol c) salt

from sea water d) camphor from salt ii). State the principle of chromatography.
Chemistry
1 answer:
REY [17]3 years ago
7 0

Answer:

A) Separating funnel method

B) Simple Distillation

C) Evaporation

D) Sublimation

E) It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

Explanation:

A)

B) Kerosene and petrol are both miscible liquids and the difference in their boiling point temperature is not more than 25°C. Thus, we make use of Simple distillation.

C) Can be separated by evaporation where the water is boiled and it evaporates and leaves the salt behind

D) To separate camphor from salt, we use sublimation so the camphor can change directly from solid to the gas state without passing through the liquid state.

E) Chromatography is used to separate components of a mixture.

It is based on the principle of separation whereby even though two substances are dissolved in the same solvent, their respective solubilities could be different. Thus, the component that has more solubility will rise fastest and will therefore get separated from the mixture.

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1) A light bulb takes in 30 of energy per second. It transfers 3j as use
natta225 [31]

Answer:

\boxed{\text{10 \%}}

Explanation:

The formula for efficiency is  

\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}

Data:

Useful energy =  3 J

Energy input  = 30 J

Calculation:

\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}

8 0
3 years ago
Building Vocabulary
Juliette [100K]

Answer:

Explanation:

Building Vocabulary

Match each term with its definition by writing the letter of the correct definition on

the line beside the term in the left column.

5. nucleus   b

6. proton     f

7. neutron   h

8. electron  d

9. atomic number    g

10. isotopes              c

11. mass number      a

12. energy level       e

a. the sum of protons and neutrons in the nucleus of an

atom

b. the very small center core of an atom

c. atoms of the same element that differ in the number

of neutrons, but have the same number of protons

d. the particle of an atom that moves rapidly in the

space outside the nucleus

e. a specific amount of energy related to the movement

of electrons in atoms

f. the particle of an atom with a positive charge

g. the number of protons in the nucleus of every atom

of an element

h. the particle of an atom that is neutral

-. mass number  a.

12. energy level    e

5 0
2 years ago
The compound 3-methylpentane is an example of
Cerrena [4.2K]

Answer:

A) An Alkaline

Explanation:

An alkane that is pentane which is substituted by a methyl group at position 3. It is used as a solvent in organic synthesis, as a lubricant and as a raw material for producing carbon black.

3 0
2 years ago
How many grams of Br are in 335g of CaBr2
ASHA 777 [7]
The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
7 0
3 years ago
A meteor falls toward Earth's surface. Given that the acceleration due to
ICE Princess25 [194]

Answer:

E = 147000  J

Explanation:

Given that,

The mass of meteor, m = 50 kg

The altitude of the meteor, h = 300 m

We need to find the potential energy of the meteor. The formula for the potential energy is given by :

E=mgh

Put all the values,

E=50\times 9.8\times 300\\\\E=147000\ J

So, the required potential energy is equal to 147000  J.

4 0
3 years ago
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