All categories

3 years ago

Compare the following in the three states of matter

Chemistry

1 answer:

Vilka [71]3 years ago

5 0

Explanation:

Anything that occupies space and has mass is called matter.

(a) Inter particle space

Solids - Atoms of a solid substance are closely packed with each other due to which there is very less or no inter particle space.
Liquids - Atoms of a liquid are little loosely packed due to which there is some inter particle space.
Gases - Atoms of a gas are very loosely packed due to which there is large inter particle space.

(b) Inter particle force of attraction

Solids - Atoms of a solid are attached to each other by strong force of attraction.
Liquids - Atoms of a liquid have slightly less force of attraction as compared to a solid substance.
Gases - Atoms of a gas have Vander waal forces. Hence, there is no inter particle force of attraction between atoms of a gas.

(c) Particle motion

Solids - There is low or negligible particle motion between atoms of a solid.
Liquids - There is high particle motion as compared to that present in a solid.
Gases - There is very high particle motion as compared to solids and liquids.

You might be interested in

How many grams of CuF2 are needed to make a 2.8 M solution

11111nata11111 [884]

Molarity is given as,

Molarity = Moles / Volume of Solution ----- (1)

Also, Moles is given as,

Moles = Mass / M.mass

Substituting value of moles in eq. 1,

Molarity = Mass / M.mass × Volume

Solving for Mass,

Mass = Molarity × M.mass × Volume ---- (2)

Data Given;

Molarity = 2.8 mol.L⁻¹

M.mass = 101.5 g.mol⁻¹

Volume = 1 L (I have assumed it because it is not given)

Putting values in eq. 2,

Mass = 2.8 mol.L⁻¹ × 101.5 g.mol⁻¹ × 1 L

Mass = 284.2 g of CuF₂

5 0

3 years ago

The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The

Olegator [25]

Answer:

$FADH_2 + Q --> FAD + QH_2$

The reactant that is reduced is $FADH_2$

Explanation:

The complete equation is as below:

$FADH_2 + Q --> FAD + QH_2$

Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.

In the above reaction, $FADH_2$ loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to $QH_2$ , hence the reducing agent.

In order words, $FADH_2$ is reduced while coenzyme Q is oxidized.

4 0

4 years ago

If 31.6 g of KMnO4 is dissolved in enough water to give 160 mL of solution, what is the molarity?

Zina [86]

Answer:

A. 1.25M

B. 19.98g

Explanation:

A. Data obtained from the question include the following:

Mass of KMnO4 = 31.6 g

Volume = 160 mL

Molarity =..?

We'll begin by calculating the number of mole KMnO4 in the solution. This is can be obtained as follow:

Mass of KMnO4 = 31.6 g

Molar mass of KMnO4 = 39 + 55 + (16x4) = 158g/mol

Number of mole of KMnO4 =..?

Mole = mass /Molar mass

Number of mole of KMnO4 = 31.6/158 = 0.2 mole

Now, we can obtain the molarity of the solution as follow:

Volume = 160 mL = 160/1000 = 0.16L

Mole of KMnO4 = 0.2 mole

Molarity = mole /Volume

Molarity = 0.2/0.16 = 1.25M

B. Data obtained from the question include the following:

Volume = 300mL

Molarity = 0.74 M

Mass of H2C2O4 =..?

First, we shall determine the number of mole H2C2O4. This is illustrated below:

Volume = 300mL = 300/1000 = 0.3L

Molarity = 0.74 M

Mole of H2C2O4 =?

Mole = Molarity x Volume

Mole of H2C2O4 = 0.74 x 0.3

Mole of H2C2O4 = 0.222 mole

Now, we can easily find the mass of H2C2O4 by converting 0.222 mole to grams as shown below:

Number of mole of H2C2O4 = 0.222 mole

Molar mass of H2C2O4 = (2x1) + (12x2) + (16x4) = 2 + 24 + 64 = 90g/mol

Mass of H2C2O4 =..?

Mass = mole x molar mass

Mass of H2C2O4 = 0.222 x 90

Mass of H2C2O4 = 19.98g

5 0

3 years ago

Which volume of oxygen, at room temperature and pressure, is needed for complete combustion

adell [148]

The molecular formula of methylpropan-1-ol is C4H10O, so the complete combustion equation is: C4H10O + 6O2 --> 4CO2 + 5H2O. This mean to completely combust 1.0mol of methylpropan-1-ol, 6 mol of O2 is required. Molar mass of O2 is 32 g/mol, so 32g/mol x 6mol = 192 g of O2 is required. At room temperature and pressure, the density of O2 is 1.3315 g/L (this can be obtained by density of gas = P/RT). So the volume of O2 = mass/density = 192g/1.3315(g/L) = 144 L = 144 dm3. The answer is B.

5 0

3 years ago

Read 2 more answers

Which element easily loses one electron to form a positive ion?

zhenek [66]

Answer:

A.Lithium (Li)

since fluorine and nitrogen gain electron and becomes negative ion.

since magnesium loose two electron.

6 0

3 years ago