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Vikki [24]
4 years ago
12

If i see i dead army person will i be asked questions and if i see the person who did it

Engineering
2 answers:
True [87]4 years ago
5 0

Answer:

Yes we take dead army people like it was on purspose because people would like to kill us off but yes you would be asked Questions and we would ask you if you saw any suspects

evablogger [386]4 years ago
5 0

Answer:

yes true it will be

Explanation:

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It is illegal to improperly dispose of antifreeze.<br> True<br> False
Reil [10]
Ehheem✔️

Explanation:
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6 0
3 years ago
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Which one of the following is a list of devices from least efficient to most efficient
Sergeu [11.5K]

Answer:

(A)-Light-Bulb, Automobile Engine, Power Plant, Electric Motor

Explanation:

To get the least efficient to the most efficient the chart below explains how to the get it

Incandescent light bulb-5%

Florescent light bulb-20%

Electric motor-90%

Power plant-35%

Automobile engine-25%

Home oil furnace-80%

4 0
3 years ago
Assume the following LTI system where the input signal is an impulse train (i.e.,x(t)=∑????(t−nT0)[infinity]n=−[infinity].a)Find
Igoryamba

Answer:

See explaination

Explanation:

The Fourier transform of y(t) = x(t - to) is Y(w) = e- jwto X(w) . Therefore the magnitude spectrum of y(t) is given by

|Y(w)| = |X(w)|

The phase spectrum of y(t) is given by

<Y(w) = -wto + <X(w)

please kindly see attachment for the step by step solution of the given problem.

4 0
3 years ago
A 10MHz clock frequency is applied to a cascaded counter consisting of a modulus-5 counter, a modulus-8 counter and two modulus-
rewona [7]

If a clock frequency is applied to a cascaded counter, The lowest output frequency available will be

  • The lowest output frequency will be = 2.5kHz

<h3>Cascade Counter</h3>

For a cascade counter,

Overall frequency = 5*8*10*10

Overall frequency = 4000

<h3>Lowest Frequency</h3>

Therefore,

the lowest frequency

F = \frac{10*10^6}{4*10^3}\\\\F = 2500Hz\\\\F = 2.5kHz

For more information on frequency, visit

brainly.com/question/17029587?referrer=searchResults

4 0
2 years ago
In the circuit below I 1=20mA V1=10 R1=400 R2=2000 R3=1000. Use node analysis to find R2
Hatshy [7]

Answer:0.2A

Explanation:

First, write KCL

i1-i2-i3=0

Then, replace currents with viltages and resistors.

V2-10v/100-v2/200-v2/400=0

V2-40=0

V2=40v

I hope it was helpful

6 0
3 years ago
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